Whole numbers Class 6 Worksheet contains 13 MCQ questions. Answers to Whole numbers Class 6 Worksheet are available after clicking on the answer. Maths Worksheets for Class 6Â help to check the concept you have learnt from detailed classroom sessions and application of your knowledge.
| Category | Maths Worksheets for Class 6 |
| Subject | Maths |
| Chapter | Whole numbers |
1. Find the successor of 56286
a) 56280
b) 56284
c) 56287
d) 56285
Answer
Answer: c) 56287
Explanation
The “Successor” of any whole number is the number, obtained by adding 1 to that number
So, the successor of 56286 + 1 = 56287
2. ​Find the predecessor of 85265 ?
a) ​85264
b) ​85266
c) ​85268
d) ​85267
Answer
Answer: a) ​85264Â
Explanation
​The “Predecessor” of any whole number is the number obtained by subtracting 1 from it
So, the predecessor of 85265 is 85265 – 1 = 85264
3. In the following pairs of number, state which number will be on right hand side of the whole number line?
( 267 , 359 )
a) 267
b) 359
Answer
Answer: b) 359
Explanation
We know that the smaller number comes on the left and bigger number comes on right on the whole number line.
So between 267 and 359
267 is smaller number
So, 267 will be on left hand side while 359 will be on right hand side
267 < 359
Hence, 359 will be on right hand side of the whole number line
4. Find the sum of 453 + 867 + 674 ?
a) 1994
b) 1993
c) 1995
d) 1996
Answer
Answer: a) 1994
Explanation
453 + ( 867 + 674 )
= 453 + 1541
= 1994
Hence, the sum of 453 , 867 and 674 is 1994
5. Find the sum of the following whole numbers ​787 + 99 ?
a) 885
b) 887
c) 886
d) 888
Answer
Answer: c) 886
Explanation
787 + 99
= 787 + ( 100 – 1 )
= ( 787 + 100 ) – 1
= 887 – 1
= 886
Hence, the sum of the given numbers is 886
6. Find: 5628 x 99
a) 557173
b) 557172
c) 557175
d) 557174
Answer
Answer: b) 557172
Explanation
5628 x ( 100 – 1 )
= ( 5628 x 100 ) – ( 5628 x 1 ) (Here, we use distributive law of multiplication over subtraction )
i.e a x (b – c) = ( a x b ) – ( a x c )
= 562800 – 5628
= 557172
So, the product of 5628 x 99 is 557172
7. Find the number which when divided by 89 gives 4 as quotient and 6 as remainder
a) 362
b) 368
c) 356
d) 350
Answer
Answer: a) 362
Explanation
Given,
Divisor = 89
Quotient = 4
Remainder = 6
In this question we have to use division algorithm
Dividend = (divisor x quotient) + remainder
= ( 89 x 4 ) + 6
= 356 + 6
= 362
Hence, the dividend is 362
Whole numbers Class 6 Worksheet
8. Find the number which when divided by 82 gives 12 as quotient and 3 as remainder?
a) 990
b) 987
c) 984
d) 981
Answer
Answer: b) 987
Explanation
Given,
Divisor = 82
Quotient = 12
Remainder = 3
In this question we have to use division algorithm
Dividend = (divisor x quotient) + remainder
= ( 82 x 12 ) + 3
= 984 + 3
= 987
Hence, the dividend is 987
9. If the Dividend = 6451 , quotient = 7 and remainder = 4 , find the Divisor ?
a) 921
b) 914
c) 917
d) 928
Answer
Answer: a) 921
Explanation
Given,
Dividend = 6451
Quotient = 7
Remainder = 4
In this question we have to use division algorithm
Dividend = (divisor x quotient) + remainder
Dividend – remainder = divisor x quotient
Divisor = (6451-4)/7
= 6447/7 = 921
Hence, the divisor is 921
10. Find the value of the following:-
( 250 x 16 ) + ( 14 x 250 )
a) 7491
b) 7500
c) 7509
d) 7507
Answer
Answer: b) 7500Â
Explanation
It follows Distributive law of multiplication over addition
Which states that a x (b + c ) = (a x b) + (a x c )
Here, a = 250
b = 16
c = 14
This question is in the form of (a x b) + (a x c )
That is, ( 250 x 16 ) + ( 14 x 250 )
( 250 x 16 ) + ( 250 x 14 ) ( NOTE : Whole number satisfy commutative property under multiplication)
i.e (a x b) = (b x a)
Here, we have 14 x 250 = 250 x 14
By distributive law, = 250 x ( 16 + 14 )
= 250 x 30
= 7500
11. Solve 20 x ( 8 – 5 ) ?
a) 60
b) 61
c) 59
d) 62
Answer
Answer: a) 60
Explanation
Here, we have two method to solve this question
By Distributive law of multiplication over subtraction a x ( b – c ) = (a x b) – (a x c)
here,
a = 20
b = 8
c = 5
1 Method
a x (b – c)
20 x ( 8 – 5 )
= 20 x 3
= 60
2 Method
(a x b) – (a x c)
( 20 x 8 ) – ( 20 x 5 )
= 160 – 100
= 60
12. A person bought 15 Books on Friday and on the next day he bought 12 Books If one book is costing him 30 rupees then how much money he had spend on Books ?
a) ₹ 360
b) ₹ 450
c) ₹ 800
d) ₹ 810
Answer
Answer: d) ₹ 810
Explanation
Total money that he spent = total number of Books x cost of one book
= ( 15 + 12 ) x 30
= 27 x 30
= 810
Total money he spent on Books is 810 rupees
13. Write the three whole numbers occurring just after 40053.
a) ​40053 , 40054 , 40055
b) ​40052 , 40051 , 40050
c) ​40054 , 40055 , 40056
d) ​40051 , 40050 , 40049
Answer
Answer: c) ​40054 , 40055 , 40056
Explanation
The next three whole number of 40053 can be obtained by adding 1, 2 and 3 to 40053
that is,
40053 + 1 = 40054
40053 + 2 = 40055
40053 + 3 = 40056
Hence the next three whole numbers of 40053 are 40054 , 40055 , 40056 respectively.
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