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Fractions Class 6 Worksheet

Please check Solutions of Fractions Class 6 Worksheet at the end of the questions.

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Fractions Class 6 Worksheet

Fractions Class 6 Worksheet

1. Is $\cfrac{7}{5}$ is a proper fraction?
a) Yes
b) No

2. Is $\cfrac{17}{9}$ is a improper fraction?
a) Yes
b) No

3. Are the following fractions are like fractions or unlike fractions?
$\cfrac{4}{5}$ , $\cfrac{5}{6}$ and $\cfrac{6}{7}$

a) Like Fractions
b) Unlike Fractions

4. Convert $\cfrac{70}{30}$ into its simplest form?
a) $\cfrac{10}{3}$
b) $\cfrac{6}{3}$
c) $\cfrac{9}{3}$
d) $\cfrac{7}{3}$

5. Convert the fraction $3\cfrac { 2 }{ 3 }$ into an improper fraction?
a) $\cfrac { 12 }{ 5 }$
b) $\cfrac { 11 }{ 3 }$
c) $\cfrac { 10 }{ 3 }$
d) $\cfrac { 13 }{ 3 }$

6. Convert $\cfrac{5}{2}$ into mixed fraction?
a) 2 $\cfrac { 2 }{ 2 }$
b) 3 $\cfrac { 1 }{ 2 }$
c) 2 $\cfrac { 1 }{ 2 }$
d) 3 $\cfrac { 2 }{ 2 }$

7. What fraction of a day is 7 hours ?
a) $\cfrac{1}{7}$
b) $\cfrac{24}{7}$
c) $\cfrac{7}{24}$
d) $\cfrac{1}{24}$

8. Find: $\cfrac{5}{9}$ of 2
a) $\cfrac{8}{9}$
b) $\cfrac{11}{9}$
c) $\cfrac{10}{9}$
d) $\cfrac{12}{9}$

9. Are $\cfrac{2}{5}$ and $\cfrac{10}{25}$ equivalent fraction ?
a) Yes
b) No

10. Find the four fractions equivalent to $\cfrac{4}{3}$

a) $\cfrac{5}{3}$ , $\cfrac{6}{3}$ , $\cfrac{7}{3}$ , $\cfrac{8}{3}$
b) $\cfrac{8}{9}$ , $\cfrac{12}{12}$ , $\cfrac{16}{15}$ , $\cfrac{20}{18}$
c) $\cfrac{8}{6}$ , $\cfrac{12}{9}$ , $\cfrac{16}{12}$ , $\cfrac{20}{15}$

11. Write a fraction equivalent to $\cfrac{5}{2}$ with numerator 25.
a) $\cfrac{25}{8}$
b) $\cfrac{25}{10}$
c) $\cfrac{25}{12}$
d) $\cfrac{10}{25}$

12. Find a fraction equivalent to $\cfrac{6}{7}$ with denominator 35 ?
a) $\cfrac{24}{35}$
b) $\cfrac{36}{35}$
c) $\cfrac{30}{35}$
d) $\cfrac{35}{30}$

13. Fill the missing number to make two Fractions equivalent ?
$\cfrac{1}{5}$ = $\cfrac{}{15}$
a) 3
b) 5

14. Compare the fractions:
$\cfrac{6}{7}$ and $\cfrac{5}{9}$
a) $\cfrac{6}{7}$ > $\cfrac{5}{9}$
b) $\cfrac{6}{7}$ < $\cfrac{5}{9}$
c) $\cfrac{6}{7}$ = $\cfrac{5}{9}$

15. Of $\cfrac{5}{7}$ and $\cfrac{6}{5}$ ,which is greater and by how much?
a) $\cfrac{5}{7}$ < $\cfrac{6}{5}$ by $\cfrac{17}{35}$
b) $\cfrac{5}{7}$ > $\cfrac{6}{5}$ by $\cfrac{19}{35}$
c) $\cfrac{5}{7}$ < $\cfrac{6}{5}$ by $\cfrac{19}{35}$
d) $\cfrac{5}{7}$ > $\cfrac{6}{5}$ by $\cfrac{17}{35}$

16. Convert the fraction as like fraction $\cfrac{4}{3}$ and $\cfrac{3}{4}$
a) $\cfrac{17}{12}$ and $\cfrac{8}{12}$
b) $\cfrac{16}{12}$ and $\cfrac{9}{12}$
c) $\cfrac{4}{4}$ and $\cfrac{3}{4}$
d) $\cfrac{4}{12}$ and $\cfrac{3}{12}$

17. Find the sum : $\cfrac{2}{3}$ + $\cfrac{5}{3}$
a) $\cfrac{7}{3}$
b) $\cfrac{4}{3}$
c) $\cfrac{5}{3}$
d) $\cfrac{8}{3}$

18. Find the sum : $\cfrac{2}{5}$ and $\cfrac{3}{7}$
a) $\cfrac{5}{35}$
b) $\cfrac{27}{35}$
c) $\cfrac{29}{35}$
d) $\cfrac{28}{35}$

19. Find the sum of 1 $\cfrac { 2 }{ 7 }$ + 4 $\cfrac { 1 }{ 3 }$
a) 7 $\cfrac { 3 }{ 21 }$
b) 4 $\cfrac { 15 }{ 21 }$
c) 5 $\cfrac { 13 }{ 21 }$
d) 6 $\cfrac { 4 }{ 21 }$

20. Find the difference : $\cfrac{5}{3}$ – $\cfrac{1}{3}$
a) $\cfrac{2}{3}$
b) $\cfrac{5}{3}$
c) $\cfrac{6}{3}$
d) $\cfrac{4}{3}$

21. Find the difference : $\cfrac{7}{6}$ and $\cfrac{7}{12}$
a) $\cfrac{8}{12}$
b) $\cfrac{7}{12}$
c) $\cfrac{6}{12}$
d) $\cfrac{9}{12}$

Fractions Class 6 Worksheet Solution

Fractions Class 6 Worksheet – Solution 1

Proper fraction is a fraction which represents the part of whole number. In proper fraction numerator is always less than its denominator.
In generalise form for any two integer ‘a’ and ‘b’
a/b where (a < b)
i.e Numerator < Denominator
Numerator = 7
Denominator = 5
Here 7 > 5
i.e, Numerator > Denominator
Hence, $\cfrac{7}{5}$ is not a proper fraction

Correct Answer – b) No

Fractions Class 6 Worksheet – Solution 2

Improper fractions are the combination of whole number and a proper fraction. Improper fraction is opposite of proper fraction, since in improper fraction numerator is greater than its denominator
In generalise form for any two integer ‘a’ and ‘b’
a/b where (a > b)
i.e Numerator > Denominator
Numerator = 17
Denominator = 9
Here, 17 > 9
i.e, Numerator > Denominator
Hence, $\cfrac{17}{9}$ is an improper fraction

Correct Answer – a) Yes

Fractions Class 6 Worksheet – Solution 3

In case of Like Fraction, the denominator of the fractions are the same.
While, In case of Unlike Fraction denominator of the fractions are not same.
In the present case, the given fractions are
$\cfrac{4}{5}$ , $\cfrac{5}{6}$ and $\cfrac{6}{7}$
Since the Denominator in the present cases are 5 , 6 , 7 which are not same. So, the given fractions are Unlike Fractions

Correct Answer – b) No

Fractions Class 6 Worksheet – Solution 4

Taking HCF of 70 and 30 is 10
Divide numerator and denominator by their HCF i.e, 10
$\cfrac{70\div 10}{30\div 10}$ = $\cfrac{7}{3}$

Correct Answer – d) $\cfrac{7}{3}$

Fractions Class 6 Worksheet – Solution 5

3 $\cfrac { 2 }{ 3 }$ “means” Quotient $\cfrac { Remainder }{ Divisor }$
So, to change mixed fraction into an improper fraction $\cfrac { \left( Quotient\times Divisor \right) +Remainder }{ Divisor }$
= $\cfrac {\left( 3\times 3 \right) + 2 }{ 3 }$
= $\cfrac { 9 + 2 }{ 3 }$
= $\cfrac { 11 }{ 3 }$

Correct Answer – b) $\cfrac { 11 }{ 3 }$

Fractions Class 6 Worksheet – Solution 6

On dividing 5 by 2
We get Quotient = 2
Remainder = 1
For a mixed fraction we have to write: $Quotient + \cfrac{Remainder}{Divisor}$
So, the mixed fraction is 2 + $\cfrac{1}{2}$ = 2 $\cfrac { 1 }{ 2 }$

Correct Answer – c) 2 $\cfrac { 1 }{ 2 }$

Fractions Class 6 Worksheet – Solution 7

As, we know that 1 day = 24 hours
So, the required fraction is $\cfrac{7}{24}$ $\cfrac{hours}{hours}$ = $\cfrac{7}{24}$

Correct Answer – c) $\cfrac{7}{24}$

Fractions Class 6 Worksheet – Solution 8

In this question ‘of’ means to multiply
When any fractions either proper or improper are multiplied with a whole number, the numerators are multiplied with whole number and the denominator will remains the same.
So, $\cfrac{5}{9}$ x 2
= $\cfrac{5}{9}$ x 2
= $\cfrac{10}{9}$
So, the answer is $\cfrac{10}{9}$

Correct Answer – c) $\cfrac{10}{9}$

Solution 9

Cross Multiplying $\cfrac{2}{5}$ and $\cfrac{10}{25}$
2 x 25 = 50
and
10 x 5 = 50
Since,
2 x 25 = 10 x 5
Hence, Value of $\cfrac{2}{5}$ = $\cfrac{10}{25}$ on cross multiplication, they are equivalent fraction.

Correct Answer – a) Yes

Fractions Class 6 Worksheet – Solution 10

To get a fraction equivalent to a given fraction, we multiply or divide the numerator and the denominator of the given fraction by the same number (except 0 or 1)
$\cfrac { 4\times 2 }{3\times 2}$ = $\cfrac{8}{6}$
$\cfrac { 4\times 3 }{3\times 3}$ = $\cfrac{12}{9}$
$\cfrac { 4\times 4 }{3\times 4}$ = $\cfrac{16}{12}$
$\cfrac { 4\times 5 }{3\times 5}$ = $\cfrac{20}{15}$
Hence, the four equivalent fractions of $\cfrac{4}{3}$ are $\cfrac{8}{6}$ , $\cfrac{12}{9}$ , $\cfrac{16}{12}$ , $\cfrac{20}{15}$

Correct Answer – c) $\cfrac{8}{6}$ , $\cfrac{12}{9}$ , $\cfrac{16}{12}$ , $\cfrac{20}{15}$

Fractions Class 6 Worksheet – Solution 11

Numerator of $\cfrac{5}{2}$ = 5
Numerator 5 has changed to 25
In other words it has become $\cfrac{25}{5}$ or 5 times of numerator of first number
So in order to obtain equivalent fraction Denominator of first fraction has to be multiplied with 5 to write an equivalent fraction
So, the denominator of new equivalent fraction = 2 x 5 = 10
Hence, the new equivalent fraction is $\cfrac{25}{10}$

Correct Answer – b) $\cfrac{25}{10}$

Fractions Class 6 Worksheet – Solution 12

Denominator of $\cfrac{6}{7}$ = 35
Denominator 7 has changed to 35
In other words it has become $\cfrac{35}{7}$ or 5 times of denominator of first number
So in order to obtain equivalent fraction Numerator of first fraction has to be multiplied with 5 to write an equivalent fraction
So, the numerator of new equivalent fraction = 6 x 5
= 30
Hence, the new equivalent fraction is $\cfrac{30}{35}$

Correct Answer – c) $\cfrac{30}{35}$

Fractions Class 6 Worksheet – Solution 13

Denominator of $\cfrac{1}{5}$ = 5
Denominator 5 has changed to 15
In other words it has become $\cfrac{15}{5}$ or 3 times of denominator of first number
So in order to obtain the Missing number, Numerator of first fraction has to be multiplied with 3
Hence, the missing number is 1 x 3 = 3

Correct Answer – a) 3

Fractions Class 6 Worksheet – Solution 14

On Cross multiplying $\cfrac{6}{7}$ and $\cfrac{5}{9}$
We multiply 6 x 9 = 54
Similarly, we multiply 7 x 5 = 35
Since, 54 > 35
Hence,
$\cfrac{6}{7}$ > $\cfrac{5}{9}$

Correct Answer – a) $\cfrac{6}{7}$ > $\cfrac{5}{9}$

Fractions Class 6 Worksheet – Solution 15

Let us compare $\cfrac{5}{7}$ and $\cfrac{6}{5}$
5 x 5 = 25 and 7 x 6 = 42
Clearly, 25 < 42
Since, $\cfrac{5}{7}$ < $\cfrac{6}{5}$
Difference = $\cfrac{6}{5}$ – $\cfrac{5}{7}$
To find the difference of unlike fraction
Firstly, we have to change the unlike fraction into equivalent like fraction and then subtract
Take LCM of 5 and 7 = 35
To change the unlike fraction into equivalent like fraction
We have to multiply $\cfrac{6 }{5}$ by 7
$\cfrac { 6\times 7 }{5\times 7}$ = $\cfrac{42}{35}$
We have to multiply $\cfrac{5 }{7}$ by 5
$\cfrac { 5\times 5 }{7\times 5}$ = $\cfrac{25}{35}$
Since, $\cfrac{42}{35}$ – $\cfrac{25}{35}$ = $\cfrac{17}{35}$
Hence, $\cfrac{5}{7}$ < $\cfrac{6}{5}$ by $\cfrac{17}{35}$

Correct Answer – a) $\cfrac{5}{7}$ < $\cfrac{6}{5}$ by $\cfrac{17}{35}$

Fractions Class 6 Worksheet – Solution 16

Step1: Find LCM of the denominators.
LCM of 3 and 4 is 12
Step 2: Divide the LCM by the denominators of the given fractions
$\cfrac{12 \div 3 }{12 \div 4 }$ = $\cfrac{4}{3}$
Step 3: Multiply the quotient by the numerator and keep denominator equal to the LCM. i.e.
$\cfrac{4 \times 4 }{12}$ = $\cfrac{16}{12}$
$\cfrac{3 \times 3 }{12}$ = $\cfrac{9}{12}$
So, $\cfrac{16}{12}$ and $\cfrac{9}{12}$ are like fractions

Correct Answer – b) $\cfrac{16}{12}$ and $\cfrac{9}{12}$

Fractions Class 6 Worksheet – Solution 17

Sum of like Fraction = $\cfrac { Sum\quad of\quad their\quad numerators }{ Common\quad denominator }$
= $\cfrac{2+5}{3}$
= $\cfrac{7}{3}$
Hence, the sum of $\cfrac{2}{3}$ and $\cfrac{5}{3}$ is $\cfrac{7}{3}$

Correct Answer – a) $\cfrac{7}{3}$

Fractions Class 6 Worksheet – Solution 18

To add unlike fraction
Firstly, we have to convert the unlike fraction into equivalent like fraction and then add
Take LCM of 5 and 7 is 35
To convert the unlike fraction into equivalent like fraction
We have to multiply $\cfrac{2}{5}$ by 7
$\cfrac { 2\times 7 }{5\times 7}$ = $\cfrac{14}{35}$
We have to multiply $\cfrac{3}{7}$ by 5
$\cfrac { 3\times 5 }{7\times 5}$ = $\cfrac{15}{35}$
Since, $\cfrac{14}{35}$ + $\cfrac{15}{35}$ = $\cfrac{29}{35}$
Hence, the sum of $\cfrac{2}{5}$ and $\cfrac{3}{7}$ = $\cfrac{29}{35}$

Correct Answer – c) $\cfrac{29}{35}$

Fractions Class 6 Worksheet – Solution 19

1 $\cfrac { 2 }{ 7 }$ + 4 $\cfrac { 1 }{ 3 }$
= $\cfrac {\left( 1\times 7 \right) + 2 }{ 7 }$ + $\cfrac {\left( 4\times 3 \right) + 1 }{ 3 }$
= $\cfrac { 7 + 2 }{ 7 }$ + $\cfrac { 12 + 1 }{ 3 }$
= $\cfrac{9}{7}$ + $\cfrac{13}{3}$
Take LCM of 7 and 3 which is equal to 21
To convert the unlike fraction into equivalent like fraction
We have to multiply $\cfrac { 9 }{ 7 }$ by 3
$\cfrac { 9\times 3 }{7\times 3}$ = $\cfrac{27}{21}$
We have to multiply $\cfrac { 13 }{ 3 }$ by 7
$\cfrac { 13\times 7 }{3\times 7}$ = $\cfrac{91}{21}$
Since, $\cfrac{27}{21}$ + $\cfrac{91}{21}$ = $\cfrac{118}{21}$ = 5 $\cfrac { 13 }{ 21 }$
Hence, the sum is 5 $\cfrac { 13 }{ 21 }$

Correct Answer – c) 5 $\cfrac { 13 }{ 21 }$

Fractions Class 6 Worksheet – Solution 20

Difference of like fraction = $\cfrac { Difference\quad of\quad their\quad numerators }{ Common\quad denominator }$
= $\cfrac{5-1}{3}$
= $\cfrac{4}{3}$
So, the difference of $\cfrac{5}{3}$ and $\cfrac{1}{3}$ is $\cfrac{4}{3}$

Correct Answer – d) $\cfrac{4}{3}$

Fractions Class 6 Worksheet – Solution 21

To find the difference of unlike fraction
Firstly, we have to change the unlike fraction into equivalent like fraction and then subtract
Take LCM of 6 and 12 is 12
To change the unlike fraction into equivalent like fraction
We have to multiply numerator and denominator of $\cfrac{7}{6}$ by 2
$\cfrac { 7\times 2 }{6\times 2}$ = $\cfrac{14}{12}$
We have to multiply numerator and denominator of $\cfrac{7}{12}$ by 1
$\cfrac { 7\times 1 }{12\times 1}$ = $\cfrac{7}{12}$
Since, $\cfrac{14}{12}$ – $\cfrac{7}{12}$ = $\cfrac{7}{12}$
So, the answer is $\cfrac{7}{12}$

Correct Answer – b) $\cfrac{7}{12}$

Fractions Class 6 Worksheet

Fractions Class 6 Worksheet

Fractions Class 6 Worksheet Solution

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