Area and Perimeter Class 6 Worksheets with Answers

Answer: d) 34 cm

Explanation
Rectangle is a four sided polygon having equal opposite sides
Given:
Length = 9 cm
Breadth = 8 cm
Perimeter of rectangle = 2 ( l + b ) units
= 2 ( 9 + 8 ) cm (Here, Length = 9 cm , Breadth = 8 cm )
= ( 2 x 17 ) cm
= 34 cm
Hence, Perimeter of rectangle is 34 cm

Answer: d) 48 cm

Explanation
Square is a four sided polygon having all four sides equal in length.
Given:
Side = 12 cm
Perimeter of square = ( 4 x Length of each side ) units
= ( 4 x 12 ) cm
= 48 cm
Hence, Perimeter of square is 48 cm

Answer: a) 20 cm

Explanation
Triangle is a three sided polygon.
Given:
Ist side = 11 cm
IInd side = 4 cm
IIIrd side = 5 cm
Perimeter of triangle = Sum of its sides
= ( Ist side + IInd side + IIIrd side ) cm
= ( 11 + 4 + 5 ) cm
= 20 cm
Hence, Perimeter of triangle is 20 cm

Answer: c) 27 cm

Explanation
An equilateral triangle is a triangle having all three sides equal in length.
Length of each side of an equilateral triangle = 9 cm
Perimeter of an equilateral triangle = ( 3 x Length of each side ) units
= ( 3 x 9 ) cm
= 27 cm
Hence, Perimeter of an equilateral triangle is 27 cm

Answer: b) 15 cm

Explanation
A regular pentagon is a five sided polygon.
All the five sides of regular pentagon are equal.
So, Length of each side of regular pentagon = 3cm
Perimeter of a regular pentagon = ( 5 x Length of each side ) units
= ( 5 x 3 ) cm
= 15 cm
Hence, Perimeter of a regular pentagon is 15 cm

Answer: b) 36 cm

Explanation
A regular decagon is a ten sided polygon that has all ten sides equal in length
Length of a regular decagon =3.6
Perimeter of a regular decagon =(10xLength of each side)units
=(10×3.6)cm
=36cm
Hence, Perimeter of a regular decagon is 36cm

Answer: a) 56 cm

Explanation
A regular octagon is an eight sided polygon.
All eight sides of regular octagon are equal.
So, Length of each side of regular octagon =7cm
Perimeter of a regular octagon = ( 8 x Length of each side ) units
= ( 8 x 7 ) cm
= 56 cm
Hence, Perimeter of a regular octagon is 56 cm

Answer: a) 60 cm²

Explanation
Given,
length = 6 cm
breadth = 10 cm
Area of rectangle = ( length x breadth ) cm²
= ( 6 x 10 ) cm²
= 60 cm²
Hence, the area of rectangle is 60 cm²

Answer: b) 16 cm²

Explanation
Sides of square = 4cm
Area of square = ( side x side ) cm²
= ( 4 x 4 ) cm²
= 16 cm²
Hence, the area of square plot is 16 cm²

Answer: d) 176 cm

Explanation
The radius of given circle is r = 28 cm
Circumference of the circle = 2∏r
= ( 2 x 22/7 x 28 ) cm
= 176 cm
Hence, the circumference of the given circle is 176 cm

Answer: c) 44 cm

Explanation
The diameter of given circle = 14 cm
Then, radius = Diameter/2 = 14/2 cm = 7 cm
Circumference of circle = 2∏r
= ( 2 x 22/7 x 7 ) cm
= 44 cm
Hence, the circumference of the given circle is 44 cm

Answer: a) 70 cm

Explanation
Let, the radius of the given circle be r cm
As we know that,
Circumference of the circle  = 2∏r cm
Given,
Circumference of a circle = 440cm
2∏r = 440  (from above)

= 70cm
Hence, the radius of the circle  = 70cm

Answer: c) 14 cm

Explanation
Let, the radius of the given circle be r cm
As we know that,
Circumference of the circle = 2∏r cm
Given,
Circumference of a cicle = 44cm
Therefore,
2∏r = 44 (from above)

= 7cm
Diameter of the circle = 2r
= (2 x 7)cm
= 14cm
Hence, the Diameter of the circle is 14 cm

Answer: a) 840 m

Explanation
Length of the field = 80 m
Breadth of the field = 60 m
Perimeter of the field = 2 (l+b) units
= 2 ( 80 + 60 ) m
= ( 2 x 140 ) m
= 280 m
Total length of rope = 3 x Perimeter of the field
= ( 3 x 280 ) m
= 840 m

Answer: d) 4.4 km

Explanation
Radius of the wheel = 140/2 cm = 70 cm

Circumference of the wheel = 2∏r
= ( 2 x 22/7 x 70 ) cm

= 440 cm
= 4.4 m ( As we know that, 1 m = 100 cm )
Distance covered by wheel in 1 revolution = Circumference of the wheel
Distance covered by wheel in 1 revolution = 4.4 m
Distance covered by wheel in 1000 revolutions = ( 4.4 x 1000 ) m
= 4400 m
= 4.4 km ( As we know that, 1 m = 1000 km )
Hence, Distance covered by wheel in 1000 revolutions is 4.4 km

Answer: b) ₹ 5000 

Explanation
Length of the room = 125 m
Breadth of the room = 10 m
Area of the floor of the room = ( 125 x 10 ) m²
= 1250 m²
Area of carpet required = 1250 m²

= 1250 m²/5 m = 1250 m/5 = 250 m
Rate of carpeting = 20 per metre.
Cost of carpeting = ₹ ( 250 x 20 ) = ₹ 5000

Answer: c) Length = 6 m , breadth = 10 m

Explanation
Let, length and breadth be 3y m and 5y m
Since, perimeter of rectangle = 2 (l+b) units
= 2 ( 3 y + 5 y ) m
= ( 2 x 8 y ) m
= 16ym
But, perimeter of rectangle = 32 m
Since, 16 y = 32
y = 32/16
y = 2
So, length = ( 3 x 2 ) m = 6 m
breadth = ( 5 x 2 ) m = 10 m

Answer: b) ₹ 2400 

Explanation
Length of the field = 65 m
Breadth of the field = 55 m
Perimeter of the field = 2 ( l+b ) units
= 2 ( 65 + 55 ) m
= ( 2 x 120 ) m
= 240 m
Cost of fencing per metre = ₹ 10
Total cost of fencing = ₹ ( 240 x 10 )
= ₹ 2400

Answer: b) 100 cm

Explanation
Given
Area = 600 cm²
breadth = 30 cm

= 600 cm²/30 cm = 600 cm/30 = 20 cm
Perimeter of the rectangle = 2 x ( l + b ) cm
= 2 x ( 30 + 20 ) cm
= ( 2 x 50 ) cm
= 100 cm
Hence, the perimeter of the rectangle is 100 cm

Answer: b) 42 cm

Explanation
Given
Area = 108 cm²
length = 12 cm

= 108 cm²/12 cm = 108 cm/12 = 9 cm
Perimeter of the rectangle = 2 x ( l + b ) cm
= 2 x ( 12 + 9 ) cm
= ( 2 x 21 ) cm
= 42 cm
Hence, perimeter of the rectangle is 42 cm