Ratio and Proportion Class 6 Worksheet

Ratio and Proportion Class 6 Worksheet contains 22 MCQ questions. Answers to Ratio and Proportion Class 6 Worksheet with answers are available after clicking on the answer. Maths Worksheets for Class 6 help to check the concept you have learnt from detailed classroom sessions and application of your knowledge.

Category Maths Worksheets for Class 6
Subject Maths
Chapter Ratio and Proportion

Ratio and Proportion Class 6 Worksheet with Answers

1. Convert the ratio 12 : 60 in its simplest form.
a) 1 : 3
b) 3 : 10
c) 11 : 5
d) 1 : 5

Answer

Answer: d) 1 : 5

Explanation
HCF of 12 and 60 is 12
Since, 12 : 60
= \cfrac{12}{60}
Dividing Both 12 and 60 by their HCF
= \cfrac{12 \div 12 }{60 \div 12 }
= \cfrac{1}{5}
= 1 : 5
Hence, the simplest form of 12 : 60 is 1 : 5

 

2. Find the ratio of 60 cm to 2.5 m?
a) 7 : 26
b) 9 : 28
c) 5 : 22
d) 6 : 25

Answer

Answer: d) 6 : 25

Explanation
Taking both the quantities in same unit, we have
2.5 m = ( 2.5 x 100 ) = 250 cm
The equation now becomes, 60 cm : 250 cm
or
= \cfrac{60}{250}
Dividing both the numbers by their HCF, i.e
= \cfrac{60 \div 10 }{250 \div 10 }
= \cfrac{6}{25}= 6 : 25
Hence, the required ratio is 6 : 25

 

3. Find the ratio of 50 g to 2 kg?
a) 1 : 40
b) 4 : 43
c) 1 : 37
d) 2 : 41

Answer

Answer: a) 1 : 40

Explanation
Taking both the quantities in same unit, we have
2 kg = ( 2 x 1000 ) = 2000 g
The equation now becomes 50 g : 2000 g
or
= \cfrac{50}{2000}
Dividing both the numbers by their HCF, i.e 50
= \cfrac{50 \div 50 }{2000 \div 50 }
= \cfrac{1}{40}= 1 : 40
Hence, the required ratio is 1 : 40

 

4. Find the ratio of 30 min to 3 hours?
a) 2 : 7
b) 4 : 9
c) 1 : 6
d) 1 : 10

Answer

Answer: c) 1 : 6

Explanation
Taking both the quantities in same unit, we have
3 hours = ( 3 x 60 ) = 180 min
The equation now becomes 30 min : 180 min
or
= \cfrac{30}{180}
Dividing both the numbers by their HCF, i.e 30
= \cfrac{30 \div 30 }{180 \div 30 }
= \cfrac{1}{6}= 1 : 6
Hence, the required ratio is 1 : 6

Ratio and Proportion Class 6 Worksheet with Answers

5. Find the ratio of 75 paise to ₹ 1.5
a) 2 : 3
b) 4 : 5
c) 1 : 4
d) 1 : 2

Answer

Answer: d) 1 : 2

Explanation
Taking both the quantities in same unit, we have
₹ 1.5 = ( 1.5 x 100 ) = 150 paise
The equation now becomes 75 paise : 150 paise
or
= \cfrac{75}{150}
Dividing both the numbers by their HCF, i.e 75
= \cfrac{75 \div 75 }{150 \div 75 }
= \cfrac{1}{2}= 1 : 2
Hence, the required ratio is 1 : 2

 

6. Find the Equivalent ratio of 5 : 4
a) \cfrac{21}{12}
b) \cfrac{4}{5}
c) \cfrac{20}{16}
d) \cfrac{18}{12}

Answer

Answer: c) \cfrac{20}{16}

Explanation
On multiplying or dividing each term of a ratio by the same non zero number, we get a ratio equivalent to the given ratio
For, \cfrac{20}{16}
Both numerator and denominator of given fraction is multiplied by same nonzero number i.e 4
\cfrac {5\times 4 }{ 4\times 4 } = \cfrac{20}{16}
\cfrac{20}{16}is an equivalent ratio of \cfrac{5}{4}
\cfrac{4}{5}is not an equivalent ratio of \cfrac{5}{4}As both 5 and 4 are not multiply by same non zero number
\cfrac{21}{12}is not an equivalent ratio of \cfrac{5}{4}As both 5 and 4 are not multiply by same non zero number
\cfrac{18}{12}is not an equivalent ratio of \cfrac{5}{4}As both 5 and 4 are not multiply by same non zero number

 

7. Two numbers are in the ratio 2 : 3 and their sum is 75. Find the numbers?
a) 30 and 45
b) 34 and 41
c) 25 and 50
d) 33 and 42

Answer

Answer: a) 30 and 45

Explanation
Let the required number be 2a and 3a
Since the sum of these two numbers is given, we can say that
2a + 3a = 75
5a = 75
a = \cfrac{75}{5}
a = 15
So, the first number is 2a = 2 x 15
= 30
Second number is 3a = 3 x 15
= 45
Hence, two numbers are 30 and 45

 

8. Divide ₹ 4500 among X and Y in the ratio 3 : 2
a) X = 2450 , Y = 1950
b) X = 2500 , Y = 2000
c) X = 2700 , Y = 1800
d) X = 2600 , Y = 1900

Answer

Answer: c) X = 2700 , Y = 1800

Explanation
Total money = ₹ 4500
Given ratio = 3 : 2
Sum of ratio terms = ( 3 + 2 )
= 5
Give: \cfrac{3}{5}part of ₹ 4500 to X
Give: \cfrac{2}{5}part of ₹ 4500 to Y
that is,
X ‘s share = ₹ ( 4500 x \cfrac{3}{5}) = ₹ 2700
Y ‘s share = ₹ ( 4500 x \cfrac{2}{5}) = ₹ 1800

 

9. Divide ₹ 1800 among X , Y and Z in the ratio 3 : 4 : 1
a) X = 675 , Y = 900 , Z = 225
b) X = 800 , Y = 675 , Z = 225
c) X = 775 , Y = 1000 , Z = 325
d) X = 675 , Y = 775 , Z = 225

Answer

Answer: a) X = 675 , Y = 900 , Z = 225

Explanation
Total money = ₹ 1800
Given ratio = 3 : 4 : 1
Sum of ratio terms = ( 3 + 4 + 1 )
= 8
X share = ₹ ( 1800 x \cfrac{3}{8}) = ₹ 675
Y share = ₹ ( 1800 x \cfrac{4}{8}) = ₹ 900
Z share = ₹ ( 1800 x \cfrac{1}{8}) = ₹ 225

Ratio and Proportion Class 6 Worksheet

10. Compare the ratios ( 2 : 1 ) and ( 1 : 4 )
a) ( 2 : 1 ) > ( 1 : 4 )
b) ( 2 : 1 ) = ( 1 : 4 )
c) ( 2 : 1 ) < ( 1 : 4 )

Answer

Answer: a) ( 2 : 1 ) > ( 1 : 4 )

Explanation
We can write
( 2 : 1 ) = \cfrac{2}{1} and ( 1 : 4 ) = \cfrac{1}{4}
Now, let us compare \cfrac{2}{1} and \cfrac{1}{4}
LCM of 1 and 4 is 4
Making the denominator of each fraction equal to 4
We have, \cfrac{2}{1} = \cfrac { 2 \times 4 }{ 1\times 4 } = \cfrac{8}{4}
and \cfrac{1}{4} = \cfrac { 1 \times 1 }{ 4\times 1 } = \cfrac{1}{4}
In case of Like fractions, the number whose numerator is greater is larger. Hence we can say \cfrac{8}{4} > \cfrac{1}{4}
That is \cfrac{2}{1} > \cfrac{1}{4}
Hence, ( 2 : 1 ) > ( 1 : 4 )




11. Find the missing terms \cfrac{4}{7} = \cfrac{}{35}
a) 21
b) 19
c) 20
d) 22

Answer

Answer: c) 20

Explanation
Let \cfrac{4}{7} = \cfrac{y}{35}
Then, 4 x 35 = 7y
7y = 4 x 35
y = \cfrac{4\quad \times \quad35 }{7}
y = 20
Hence, \cfrac{4}{7} = \cfrac{20}{35}

 

12. Find the missing terms:
\cfrac{56}{104} = \cfrac{}{13} = \cfrac{14}{}
a) 7, 26
b) 6, 27
c) 8, 27
d) 9, 25

Answer

Answer: a) 7 , 26

Explanation
Let \cfrac{56}{104} = \cfrac{y}{13}
Then, 56 x 13 = 104y
104y = 56 x 13
y = \cfrac{56 \times 13 }{104}
y = 7
Since, \cfrac{56}{104} = \cfrac{7}{13}
Again, let \cfrac{7}{13} = \cfrac{14}{z}
Then, 7z = 14 x 13
z = \cfrac{14 \times 13 }{7}
z = \cfrac{182}{7}
z = 26
Since, \cfrac{7}{13} = \cfrac{14}{26}
Hence, \cfrac{56}{104} = \cfrac{7}{13} = \cfrac{14}{26}

 

13. Are the ratios 90 cm : 180 cm and 180 m : 340 m in proportion?
a) Yes
b) No

Answer

Answer: b) No

Explanation
We have 90 cm : 180 cm
= 90 : 180
= \cfrac{90}{180}
=\cfrac{90 \div 90 }{180 \div 90 }(HCF of 90 and 180 is 90 )
= \cfrac{1}{2}
180 m : 340 m
= 180 : 340
= \cfrac{180}{340}
=\cfrac{180 \div 20 }{340 \div 20 }( HCF of 180 and 340 is 20 )
= \cfrac{9}{17}
Since, the ratios 90 cm : 180 cm and 180 m : 340 m are equal to \cfrac{1}{2} and \cfrac{9}{17} . So, they are not in proportion.

 

14. Are 6 , 9 , 10 , 15 in proportion?
a) Yes
b) No

Answer

Answer: a) Yes

Explanation
We have, 6 : 9 = \cfrac{6}{9} = \cfrac{6 \div 3 }{9 \div 3 }= \cfrac{2}{3}
and 10 : 15 = \cfrac{10}{15} = \cfrac{10 \div 5 }{15 \div 5 }= \cfrac{2}{3}
Since, 6 : 9 = 10 : 15
Hence, 6 , 9 , 10 , 15 are in Proportion
Alternative method: Product of extremes = Product of means
Here, Means are 9 and 10
Extremes are 6 and 15
Product of extremes = 6 x 15 = 90
Product of means = 9 x 10 = 90
Since, Product of extremes = Product of means
Hence, 6 , 9 , 10 , 15 are in Proportion

 

15. If 2 : 4 : : y : 6, find the value of y?
a) 4
b) 3
c) 5
d) 6

Answer

Answer: b) 3

Explanation
Clearly, Product of means = Product of extremes
y x y = 4 x 16
{ y }^{ 2 } = 4 x 16
{ y }^{ 2 } = 64
Hence, y = 8

 

16. If 4 : y : : y : 16, find the value of y?
a) 8
b) 9
c) 7
d) 10

Answer

Answer: a) 8

Explanation
Clearly, Product of means = Product of extremes
y x y = 4 x 16
{ y }^{ 2 } = 4 x 16
{ y }^{ 2 } = 64
Hence, y = 8

 

17. If 2, 12, y are in proportion, find the value of y?
a) 71
b) 73
c) 72
d) 74

Answer

Answer: c) 72

Explanation
2 , 12 , y are in proportion
Which means 2 , 12 , 12 , y are in proportion
i.e, 2 : 12 : : 12 : y
Product of means = Product of extremes
here,
means = 12 and 12
extremes = 2 and y
12 x 12 = 2 x y
144 = 2 x y
y = \cfrac{144}{2}
Hence, y = 72

 

18. There are 45 girls and 75 boys in class. Then find the ratio of number of boys to the number of girls?
a) 3 : 2
b) 5 : 3
c) 2 : 4
d) 5 : 6

Answer

Answer: b) 5 : 3

Explanation
\cfrac { Number\quad of\quad \quad boys }{ Number\quad of\quad girls} = \cfrac{75}{45}
On simplifying,
\cfrac { Number\quad of\quad \quad boys }{ Number\quad of\quad girls} = \cfrac{75 \div 15 }{45 \div 15 }( HCF of 75 and 45 is 15 )
= \cfrac{5}{3}= 5 : 3
Hence,the ratio is 5 : 3

 

19. 8 workers can reap a field in 12 days, in how many days can 4 workers reap the same field?
a) 26 days
b) 25 days
c) 24 days
d) 23 days

Answer

Answer: b) No

Explanation
Clearly, less workers will take the more days.
And, more workers will take less days.
8 workers can reap a field in = 12 days
1 worker can reap a field in = ( 12 x 8 ) days
Hence, 4 workers can reap a field in = \cfrac{12 \times 8 }{4}days = 24 days
Hence, 4 workers can reap a field in 24 days

 

20. If 12 mangoes cost ₹ 36 , what is the cost of 15 mangoes
a) ₹ 30
b) ₹ 45
c) ₹ 57
d) ₹ 46

Answer

Answer: b) ₹ 45

Explanation
Cost of 12 mangoes = ₹ 36
Cost of 1 mango = ₹ \cfrac{36}{12}
Cost of 15 mangoes = ₹ \cfrac{36\times 15 }{12}
= ₹ 45

 

21. If a mechanic earns ₹ 2000 at 2 cars. How much he will earn in 1 day, if in a day he receive 12 cars?
a) ₹ 12345
b) ₹ 12000
c) ₹ 12213
d) ₹ 11981

Answer

Answer: b) ₹ 12000

Explanation
Earning on 2 cars = ₹ 2000
1 car = ₹ \cfrac{2000}{2} = ₹ 1000
Earning on 12 cars = ₹ ( 1000 x 12 )
= ₹ 12000

 

22. If a student pays ₹ 15000 as annual fees to the school. Find his fee per month?
a) ₹ 1250
b) ₹ 1387
c) ₹ 1393
d) ₹ 1225

Answer

Answer:a) ₹ 1250

Explanation
Annually means 1 year = 12 months
Fees of 12 month = ₹ 15000
Fees of 1 month = ₹ \cfrac{15000}{12}
= ₹ 1250

 

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