NCERT Solutions For Class 10 Maths Chapter 3 Exercise 3.2 – Pair of Linear Equations in two Variables 

Download NCERT Solutions For Class 10 Maths Chapter 3 Exercise 3.2 – Pair of Linear Equations in two Variables. This Exercise contains 7 questions, for which detailed answers have been provided in this note. In case you are looking at studying the remaining Exercise for Class 10 for Maths NCERT solutions for other Chapters, you can click the link at the end of this Note.

NCERT Solutions For Class 10 Maths Chapter 3 Exercise 3.2 – Pair of Linear Equations in two Variables

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NCERT Solutions For Class 10 Maths Chapter 3 Exercise 3.2 – Pair of Linear Equations in two Variables 

1. Form the pair of linear equations in the following problems and find their solutions graphically.

i. 10 student of class X took part in mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.

ii. 5 pencils and 7 pens together cost 50 whereas 7 pencil and 5 pens together cost 46. Find the cost of one pencil and that of one pen.

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Addition of Three 3-digit numbers with Regrouping | Maths Grade 2

Addition of Three 3-digit numbers with Regrouping

 

Example 1:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

7 + 5 + 6 = 18

Since the number is more than 9, we need to carry over 1 to the tens place.

Step 2: Adding the digits at tens place and the carry of 1,

2 + 4 + 5 + 1 = 12

Since the number is more than 9, we need to carry over 1 to the hundreds place.

Step 3: Adding the digits at hundreds place and carry 1,

3 + 2 + 2 + 1 = 8

Hence, the sum of the given numbers is 828

 

Example 2:- Add the following?

Step 1: Adding the digits at one’s place,

5 + 3 + 2 = 10

Since the number is more than 9, we need to carry over 1 to the tens place.

Step 2: Adding the digits at tens place and the carry of 1,

7 + 9 + 0 + 1 = 17

Since the number is more than 9, we need to carry over 1 to the hundreds place.

Step 3: Adding the digits at hundreds place and carry 1,

2 + 5 + 1 + 1 = 9

Hence, the sum of the given numbers is 970

 

Example 3:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

5 + 2 + 5 = 12

Since the number is more than 9, we need to carry over 1 to the tens place.

Step 2: Adding the digits at tens place and the carry of 1,

8 + 7 + 2 + 1 = 18

Since the number is more than 9, we need to carry over 1 to the hundreds place.

Step 3: Adding the digits at hundreds place and carry 1,

2 + 4 + 2 + 1 = 9

Hence, the sum of the given numbers is 982

Addition of Three 3-digit numbers Ones to Tens | Maths Grade 2

Addition of Three 3-digit numbers with Regrouping Ones to Tens

 

Example 1:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

2 + 3 + 5 = 10

Since the number is more than 9, we need to carry over 1 to the tens place.

Step 2: Adding the digits at tens place and the carry of 1,

5 + 0 + 3 + 1 = 9

Step 3: Adding the digits at hundreds place,

6 + 1 + 2 = 9

Hence, the sum of the given numbers is 990

 

Example 2:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

6 + 3 + 5 = 14

Since the number is more than 9, we need to carry over 1 to the tens place.

Step 2: Adding the digits at tens place and the carry of 1,

4 + 0 + 0 + 1 = 5

Step 3: Adding the digits at hundreds place,

3 + 2 + 3 = 8

Hence, the sum of the given numbers is 854

 

Example 3:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

7 + 0 + 7 = 14

Since the number is more than 9, we need to carry over 1 to the tens place.

Step 2: Adding the digits at tens place and the carry of 1,

4 + 3 + 0 + 1 = 8

Step 3: Adding the digits at hundreds place,

1 + 2 + 1 = 4

Hence, the sum of the given numbers is 484

Addition of Three 3-digit numbers without Regrouping | Maths Grade 2

Addition of Three 3-digit numbers without Regrouping

 

Example 1:- Add the following?

 

Explanation:

Step 1: Adding the digits at ones place,

2 + 3 + 1 = 6

Step 2: Adding the digits at tens place,

3 + 2 + 4 = 9

Step 3: Adding the digits at hundreds place,

2 + 1 + 3 = 6

Hence, the sum of the given numbers is 696

 

Example 2:- Add the following?

 

Explanation:

Step 1: Adding the digits at ones place,

6 + 0 + 3 = 9

Step 2: Adding the digits at tens place,

5 + 4 + 0 = 9

Step 3: Adding the digits at hundreds place,

3 + 1 + 2 = 6

Hence, the sum of the given numbers is 699

 

Example 3:- Add the following?

 

Explanation:

Step 1: Adding the digits at ones place,

3 + 3 + 0 = 6

Step 2: Adding the digits at tens place,

2 + 1 + 6 = 9

Step 3: Adding the digits at hundreds place,

1 + 1 + 3 = 5

Hence, the sum of the given numbers is 596

Addition of Three 2-digit numbers with Regrouping | Maths Grade 2

Addition of Three 2-digit numbers with Regrouping

 

Example 1:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

3 + 3 + 4 = 10

Since the number is more than 9, we need to carry over 1 to the tens place.

 

Step 2: Adding the digits at tens place and the carry of 1,

2 + 1 + 2 + 1 = 6

Hence, the sum of the given numbers is 60

 

Example 2:- Add the following?

 

 

 

Step 1: Adding the digits at one’s place,

9 + 0 + 9 = 18

Since the number is more than 9, we need to carry over 1 to the tens place.

 

Step 2: Adding the digits at tens place and the carry of 1,

4 + 1 + 1 + 1 = 7

Hence, the sum of the given numbers is 78

 

Example 3:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

7 + 9 + 3 = 19

Since the number is more than 9, we need to carry over 1 to the tens place.

Step 2: Adding the digits at tens place and the carry of 1,

5 + 2 + 1 + 1 = 9

Hence, the sum of the given numbers is 99

Addition of Three 2-digit numbers without Regrouping | Maths Grade 2

Addition of Three 2-digit numbers without Regrouping

 

Example 1:- Add the following?

 

Explanation:

Step 1: Adding the digits at ones place,

2 + 3 + 2 = 7

 

Step 2: Adding the digits at tens place,

1 + 1 + 4 = 6

Hence, the sum of the given numbers is 67

 

Example 2:- Add the following?

 

Explanation:

Step 1: Adding the digits at ones place,

1 + 0 + 2 = 3

 

Step 2: Adding the digits at tens place,

2 + 5 + 1 = 8

Hence, the sum of the given numbers is 83

 

Example 3:- Add the following?

 

Explanation:

Step 1: Adding the digits at ones place,

4 + 1 + 1 = 6

 

Step 2: Adding the digits at tens place,

2 + 1 + 3 = 6

Hence, the sum of the given numbers is 66

Addition of 2-digit numbers with Regrouping | Maths Grade2

Addition of 2-digit numbers with Regrouping

 

 

Example 1:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

6 + 6 = 12

Since the number is more than 9, we need to carry over 1 to the ten’s place

 

Step 2: Adding the digits at ten’s place and the carry of 1,

1 + 1 + 1 = 3

Hence, the sum of the given numbers is 32

 

Example 2:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

6 + 8 = 14

Since the number is more than 9, we need to carry over 1 to the ten’s place

 

Step 2: Adding the digits at tens place and the carry of 1,

3 + 1 + 1 = 5

Hence, the sum of the given numbers is 54

 

Example 3:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

2 + 9 = 11

Since the number is more than 9, we need to carry over 1 to the ten’s place.

 

Step 2: Adding the digits at tens place and the carry of 1,

4 + 1 + 1 = 6

Hence, the sum of the given numbers is 61

Addition of Two 3-digit number with Regrouping | Maths Grade2

Addition of Two 3-digit number with Regrouping

 

 

Example 1:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

3 + 8 = 11

Since the number is more than 9, we need to carry over 1 to the tens place.

 

Step 2: Adding the digits at tens place and the carry of 1,

5 + 2 + 1 = 8

 

Step 3: Adding the digits at hundred’s place,

3 + 2 = 5

Hence, the sum of the given numbers is 581

 

Example 2:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

6 + 9 = 15

Since the number is more than 9, we need to carry over 1 to the tens place.

 

Step 2: Adding the digits at tens place and the carry of 1,

4 + 4 + 1 = 9

 

Step 3: Adding the digits at hundreds place

3 + 5 = 8

Hence, the sum of the given numbers is 895

 

Example 3:- Add the following?

 

Explanation:

Step 1: Adding the digits at one’s place,

9 + 1 = 10

Since the number is more than 9, we need to carry over 1 to the tens place.

 

Step 2: Adding the digits at tens place and the carry of 1,

0 + 9 + 1 = 10

 

Step 3: Adding the digits at hundreds place and the carry of 1,

5 + 3 + 1 = 9

Hence, the sum of the given numbers is 900