Download NCERT Solutions For Class 10 Maths Chapter 3 Exercise 3.2 – Pair of Linear Equations in two Variables. This Exercise contains 7 questions, for which detailed answers have been provided in this note. In case you are looking at studying the remaining Exercise for Class 10 for Maths NCERT solutions for other Chapters, you can click the link at the end of this Note.

### NCERT Solutions For Class 10 Maths Chapter 3 Exercise 3.2 – Pair of Linear Equations in two Variables

**NCERT Solutions For Class 10 Maths Chapter 3 Exercise 3.2 – Pair of Linear Equations in two Variables **

**1. Form the pair of linear equations in the following problems and find their solutions** **graphically.**

**i. 10 student of class X took part in mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.**

**ii. 5 pencils and 7 pens together cost ****₹ ****50 whereas 7 pencil and 5 pens together cost ****₹ ****46. Find the cost of one pencil and that of one pen.**

**Solution :**

**(i)** Let the number of girls = x

the number of boys = y

According to the given conditions we can write

Total number of students is 10, hence

x + y = 10 ..(1)

Number of girls is 4 more than the number of boys, hence

x = y + 4 ..(2)

To plot graph for equation (1), points which satisfy the equation are as follows

To plot graph for equation (2), points which satisfy the equation are as follows

Hence the graphical representation of equations (1) and (2) is as follows

(ii) Let the cost of one pencil = x

Cost of one pen = y

According to the given conditions we have two equations as follows

5x + 7y = 50 ….(1)

7x + 5y = 46 ….(2)

To plot graph for equation (1), points which satisfy the equation are as follows

To plot graph for equation (2), points which satisfy the equation are as follows

Hence the graphical representation of equations (1) and (2) is as follows

**2. On comparing the ratios (a _{1}**

**/a**

_{2}), (b_{1}**/b2), (c**

_{1}**/c**

_{2}), find out whether the lines representing the following pairs of linear equations intersect at points, are parallel or coincide.**i. 5x-4y+8=0, 7x+6y-9=0 **

**ii. 9x+3y+12=0, 18x+6y+24=0**

**iii. 6x-3y+10=0, 2x-y+9=0**

**Solution:**

We know that a pair of linear equation

a_{1}x+b_{1}y=c_{1} …(1)

a_{2}x+b_{2}y=c_{2 }…(2)

i. Intersecting if (a_{1}/a_{2}) ≠ (b_{1}/b2)

ii. Coincident if (a_{1}/a_{2}) = (b_{1}/b2) = (c_{1, }c_{2})

iii. Parallel if (a_{1}/a_{2}) = (b_{1}/b2) ≠ (c_{1, }c_{2})

**i.** 5x – 4y + 8 = 0, 7x+6y-9=0

Here,

(a_{1}/a_{2})= (5/7)

(b_{1}/b2)= (-4/6) = (-2/3)

Since, (a_{1}/a_{2}) ≠ (b_{1}/b2)

Hence, the given pair of equations intersects at a point.

**ii.** 9x+3y+12=0, 18x+6y+24=0

Here,

(a_{1}/a_{2}) = 9/18 = 1/2

(b_{1}/b2) = 3/6 = 1/2

(c_{1/ }c_{2}) = 12/24 = 1/2

Since, (a_{1}/a_{2}) =(b_{1}/b2) =(c_{1/ }c_{2})

Hence, the given pair of linear equations are coincident.

**iii.** 6x-3y+10=0 , 2x-y+9=0

Here,

(a_{1}/a_{2}) = 6/2 = 3/1

(b_{1}/b2) = (-3/-1) = (3/1)

(c_{1/ }c_{2}) = 10/9

Since, (a_{1}/a_{2}) = (b_{1}/b2) ≠ (c_{1/ }c_{2})

Hence, the given pair of linear equations are parallel.

**3. On comparing the ratios (a _{1/}a_{2}), (b_{1}/b2), (c_{1, }c_{2}).**

**Find out whether the lines representing the following pairs of equations are consistent or inconsistent.**

**i. 3x+2y=5, 2x-3y=7 **

**ii. 2x-3y=8, 4x-6y=9**

**iii. (3/2)x+(5/3)**

**y = 7, 9x-10y = 14**

**iv. 5x-3y=11, -10x+6y=-22**

**v. (4/3)x**

**+ 2**

**y**

**= 8**

**; 2x + 3y = 12**

**Solution :**

we know that a pair of linear equation

a_{1}x+b_{1}y=c_{1} …(1)

a_{2}x+b_{2}y=c_{2 }…(2)

Intersecting if (a_{1}/a_{2}) ≠ (b_{1}/b2), hence consistent

Coincident if (a_{1}/a_{2}) = (b_{1}/b2) = (c_{1/ }c_{2}), hence consistent

Parallel if (a_{1}/a_{2}) = (b_{1}/b2) ≠ (c_{1/ }c_{2}), hence inconsistent

**i.** 3x+2y=5, 2x-3y=7

Here,

(a_{1}/a_{2}) = 3/2

(b_{1}/b2) = (2/-3)

Since, (a_{1}/a_{2}) ≠ (b_{1}/b2)

Hence, the given pair of linear equations are consistent.

**ii.** 2x-3y=8, 4x-6y=9

Here,

(a_{1}/a_{2}) = 2/4 = 1/2

(b_{1}/b2) = (-3/-6) = 1/2

(c_{1/ }c_{2}) = 8/9

Since, (a_{1}/a_{2}) = (b_{1}/b2) ≠ (c_{1/ }c_{2})

Hence, the given pair of linear equations are inconsistent.

**iii.** (3/2)x+ (5/3)y = 7, 9x-10y = 14

Here,

Since, (a_{1}/a_{2}) ≠ (b_{1}/b2)

Hence, the given pair of linear equations are consistent.

**iv.** 5x-3y=11, -10x+6y=-22

Here,

(a_{1}/a_{2}) = (5/-10) = (1/-2)

(b_{1}/b2) = (-3/6) = (-1/2)

(c_{1/ }c_{2}) = (11/-22) = (1/-2)

Since, (a_{1}/a_{2}) = (b_{1}/b2) = (c_{1/ }c_{2})

Hence, the given pair of linear equations are consistent.

**v.** (4/3)x + 2y = 8 ; 2x + 3y = 12

Here,

(b_{1}/b2) = 2/3

(c_{1/ }c_{2}) = 8/12 = 2/3

Since, (a_{1}/a_{2}) = (b_{1}/b2) =(c_{1/ }c_{2})

Hence, the given pair of linear equations are consistent.

**4. Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically:**

**i. x + y = 5, 2x + 2y = 10 **

**ii. x – y = 8,3x – 3y = 16**

**iii. 2x + y – 6 = 0, 4x – 2y – 4 = 0**

**iv. 2x – 2y – 2 = 0, 4x – 4y – 5 = 0**

**Solution :**

**i.** x + y = 5, 2x + 2y = 10

Here,

(a_{1}/a_{2}) = 1/2

(b_{1}/b2) = 1/2

(c_{1/ }c_{2}) = 5/10 = 1/2

Since, (a_{1}/a_{2}) = (b_{1}/b2) = (c_{1/ }c_{2})

Hence, the given pair of linear equations are consistent.

To plot graph for equation (1), points which satisfy the equation are as follows

To plot graph for equation (2), points which satisfy the equation are as follows

Hence the graphical representation of equations (1) and (2) is as follows

**ii.** x – y = 8,3x – 3y = 16

Here,

(a_{1}/a_{2}) = 1/3

(b_{1}/b2) = (-1/-3) = 1/3

(c_{1/ }c_{2}) = 8/16 = 1/2

Since, (a_{1}/a_{2}) = (b_{1}/b2) ≠ (c_{1/ }c_{2})

Hence, the given pair of linear equations are inconsistent.

**iii.** 2x + y – 6 = 0, 4x – 2y – 4 = 0

Here,

(a_{1}/a_{2}) = 2/4 = 1/2

(b_{1}/b2) = (1/-2)

Since, (a_{1}/a_{2}) ≠ (b_{1}/b2)

Hence, the given pair of linear equations are consistent.

To plot graph for equation (1), points which satisfy the equation are as follows

To plot graph for equation (2), points which satisfy the equation are as follows

Hence the graphical representation of equations (1) and (2) is as follows

**iv.** 2x – 2y – 2 = 0, 4x – 4y – 5 = 0

Here,

(a_{1}/a_{2}) = 2/4 = 1/2

(b_{1}/b2) = (-2/-4) = 1/2

(c_{1/ }c_{2}) = (-2/-5) = 2/5

Since, (a_{1}/a_{2}) = (b_{1}/b2) ≠ (c_{1/ }c_{2})

Hence, the given pair of linear equations are inconsistent.

**5. Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36m. Find the dimensions of the garden.**

**Solution:**

Let the breadth of the garden be x and length be y.

According to question,

Half of the perimeter = 36 m

Hence,

(1/2) [2(x+y)] = 36

Or, (x + y) = 36 ..(1)

Also,

Length is 4 more than breadth

Hence,

y = x + 4 ..(2)

To plot graph for equation (1), points which satisfy the equation are as follows

To plot graph for equation (2), points which satisfy the equation are as follows

Hence the graphical representation of equations (1) and (2) is as follows

From the graph it is evident that the lines intersect at (16,20).

Therefore, we get the dimensions of the garden as

Length = 20 m

Breadth = 16 m.

**6. Given the linear equation 2x + 3y – 8 = 0, write another linear equation in two variables such that the geometrical representation of the pair so formed is: **

**(i) intersecting lines**

**(ii) parallel lines**

**(iii) coincident lines**

**Solution :**

**i.** Another linear equation intersecting the given equation i.e 2x + 3y – 8 = 0 is 2x + y – 8 = 0

as (a_{1}/a_{2}) ≠ (b_{1}/b2)

**ii.** Another linear equation parallel to the given equation i.e 2x + 3y – 8 = 0 is 2x + 3y – 10 = 0,

as (a_{1}/a_{2}) = (b_{1}/b2) ≠ (c_{1/ }c_{2})

**iii.** Another linear equation coincident to the given equation i.e 2x + 3y – 8 = 0 is 4x + 6y – 16 = 0,

as (a_{1}/a_{2}) = (b_{1}/b2) = (c_{1/ }c_{2})

**7. Draw the graphs of the equations x – y + 1 = 0 and 3x + 2y – 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region.**

**Solution :**

For x – y + 1 = 0 the points which satisfy this equation are as follows

For 3x + 2y – 12 = 0 the points which satisfy this equation are as follows

The graph is as follows

We can see that the vertices of the triangle are (-1,0),(4,0) and (2,3).

**NCERT Solutions for Class 10 Maths Chapter 3 Exercise 3.2 – Pair of Linear Equations in two Variables, has been designed by the NCERT to test the knowledge of the student on the topic – Graphical Method of Solution of a Pair of Linear Equations**

**Download NCERT Solutions For Class 10 Maths Chapter 3 Exercise 3.2 – Pair of Linear Equations in two Variables **