Square and Square Roots Class 8 MCQ with Answers Maths are covered in this Article. Square and Square Roots Class 8 MCQs Test contains 11 questions. Answers to MCQs on Square and Square Roots Class 8 Maths are available at the end of the last question. These MCQ have been made for Class 8 students to help check the concept you have learnt from detailed classroom sessions and application of your knowledge.
Board | CBSE |
Textbook | Maths (NCERT) |
Class | Class 8 |
Chapter | Chapter 6 Square and Square Roots |
Square and Square Roots Class 8 MCQ with Answers
1.What is the least number by which 175 should be multiplied, so that the product of the two numbers would be a perfect square ?
(a) 7
(b) 21
(c) 12
Answer
Answer: (a) 7
Explanation: If we find the factors of 175 , we would get 175 = 5 x 5 x 7
If we draw out the factors in pairs, we would notice that we have pair of 5 , but 7 is the only single number, which is not in pair.
Therefore if 175 is multiplied by 7 then the product would be a complete square.
2.What is the value of (107)2 ?
(a) 11449
(b) 11549
(c) 11409
Answer
Answer: (a) 11449
Explanation: We know that(a + b)2=a2+b2+2ab
When finding the square of a larger number, we can use this equation to break the larger number into parts, whose squares can be easily calculated
We can write 107 as ( 100 + 7 )
So
(107)2=(100+7)2
Applying(a + b)2=a2+b2+2ab
(100)2+72+ 2 x 100 x 7
= 10000 + 49 + 1400
= 11449
3.Solve (48×48-2×12+48+12×12)/(18)2=?
(a) 4
(b) 12
(c) 9
Answer
Answer: (a) 4
Explanation: We know that (a−b)2=a2+b2−2ab
If we compare the above equation with the Numerator, we would find that the equation can be re-written as
= (48)2−2×12×48+(12)2
Or we can say that the given equation has value of
a = 48 and b = 12
So we can replace the numeration
48 x 48 – 2 x 12 x 48 + 12 x 12 with (48−12)2=(36)2
Now putting these values in Numerator, we would get
(36)2/(18)2 = 1296/324 = 4
Square and Square Roots Class 8 MCQ with Answers
4.If √18 = 4.24 ,what is the value √(2/9)?
(a) 0.47
(b) 0.59
(c) 0.71
Answer
Answer: (a) 0.47
Explanation: In order to solve these type of problems, we first need to equate the value which has to be solved 29−−√ of the given equation in the given equation
We can write √18 = 4.24
Replacing 18 by ( 2 x 9 ) in the given equation, and dividing both the sides by 9 , we would get
√(2×9)/(9×9)
= √(18/81)
= √18/9
= 4.24/9
= 0.47
5.If (26)2-(22)2 = {(42)2-(40)2} x Y , then the value of Y is ?
(a) 41/48
(b) 48/41
(c) 51/43
Answer
Answer: (b) 48/41
Explanation: Since,
(a2−b2)=(a−b)(a + b)
We can rewrite both the equation as
262 – 222 = {(42)2 – (40)2} x Y
( 26 + 22 ) x ( 26 – 22 ) = ( 42 + 40 ) x ( 42 – 40 ) x Y
48 x 4 = 82 x 2 x Y
192 = 164 x Y
Or,
Y = 192/164
Y = 48/41
6.If √x/33 =5/11 , then the value of x is ?
(a) 125
(b) 225
(c) 25
Answer
Answer: (b) 225
Explanation: √x/33 = 5/11
√x = (5×33)/11
√x = 5 x 3
√x = 15
On squaring both the sides
x = 152
x = 15 x 15
x = 225
7.Find the value of (56)2 – (55)2 + 42
(a) 147
(b) 97
(c) 127
Answer
Answer: (c) 127
Explanation: (56)2−(55)2+42
We know that(a2−b2)=(a−b)(a +b)
a = 56 and b = 55
= ( 56 + 55 ) ( 56 – 55 ) + 16
= 111 x 1 + 16
= 111 + 16
= 127
8.The value of (16)2 – (12)2?
(a) 116
(b) 112
(c) 107
Answer
Answer: (b) 112
Explanation: We know that(a)2−(b)2=(a−b)(a +b)
If we compare the above equation to the problem at hand, we find that
a = 16 and b = 12
So we can rewrite the above equation as
162−122 = ( 16 + 12 ) ( 16 – 12 )
= 28 x 4
= 112
Square and Square Roots Class 8 MCQ with Answers
9.In a conference hall of a school, 225 students were sitting in such a way that there were as many rows as there were students in a row. How many rows were there?
(a) 19
(b) 15
(c)10
Answer
Answer: (b) 15
Explanation: Let the number of rows = Number of students in a row = x
Total number of students = Number of rows x Number of students in a row
Then
x x x = 225
x2 = 225
x = √ 225
= √ 3 x 3 x 5 x 5
= 3 x 5
= 15
Hence, the number of rows = Number of students in a row = 15
10.A group of students decided to collect as many paisa from each member of the group as is the number of members. If the total collection amounts to Rs. 21.16 , the number of members in the group is ?
(a) 46
(b) 36
(c) 42
Answer
Answer: (a) 46
Explanation: Funds collected in paisa= 21.16 x 100
= 2116
Funds collected= Numbers of the members of the group x Paisa collected from each member
Or
2116= Numbers of the members of the group x Paisa collected from each member
Let the Number of members of the group= x
Then Paisa collected from each member= x
Substituting these values in the given equation
2116= x x x
x2= 2116
Or,
x = √2116
x = 46
Numbers of the members of the group = 46
11.Which one of the following is perfect square ?
55557 , 6678 , 3930 , 1000000
(a) 55557
(b) 6678
(c) 1000000
(d) 3930
Answer
Answer: (c) 1000000
Explanation: The numbers which end with 2 , 3, 7 or 8 cannot be the complete squares.
Since the numbers 55557 and 6678 ends with 7 and 8 , therefore, they cannot be perfect square.
If the number of zeros at the end of any number is odd, such a number will not be a perfect square.
As the number of zeros at the end of 3930 are odd, therefore, it will not be a perfect square.
However, 1000000 can be written as = 1000 x 1000
Hence, 1000000 is a perfect square.
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Frequently Asked Questions on Square and Square Roots Class 8 MCQ with Answers
1. Are these MCQs on Square and Square Roots Class 8 are based on 2021-22 CBSE Syllabus?
Yes. There are 11 MCQ’s on this Chapter in this blog.
2. Are you giving all the chapters of Maths Class 8 MCQs with Answers which are given in CBSE syllabus for 2021-22 ?
Yes, we are providing all the chapters of Maths Class 8 MCQs with Answers.