Fractions Worksheets Grade 5

Fractions Worksheets Grade 5 contains 14 MCQ questions. Answers to Fractions Worksheets Grade 5 are available after clicking on the answer. Maths Worksheets for Class 5 help to check the concept you have learnt from detailed classroom sessions and application of your knowledge.

Category Maths Worksheets for Class 5
Subject Maths
Chapter Fractions

Fractions Worksheets Grade 5

Q.1) Compare \cfrac{11}{3} and \cfrac{5}{3}
a) \cfrac{11}{3} < \cfrac{5}{3}
b) \cfrac{11}{3} > \cfrac{5}{3}

Answer

Answer: b) \cfrac{11}{3} > \cfrac{5}{3}

Explanation
On Cross Multiplication \cfrac{11}{3} and \cfrac{5}{3}
We multiply 11 x 3 = 33
Similarly, we multiply 3 x 5 = 15
The Fraction whose Numerator has higher value, after multiplication, is greater Fraction
Since, 33 > 15
Hence, \cfrac{11}{3} > \cfrac{5}{3}


 

Q.2) Convert \cfrac{59}{10} into Mixed Fraction.
a) 5\cfrac{5}{10}
b) 5\cfrac{7}{10}
c) 5\cfrac{9}{10}

Answer

Answer: c) 5\cfrac{9}{10}

Explanation
On dividing 59 by 10
We get, Quotient = 5
Remainder = 9
For a mixed Fraction we have to write Quotient + \cfrac { Remainder }{ Divisor }
So, the mixed Fraction is 5 + \cfrac{9}{10} = 5\cfrac{9}{10}


 

Q.3) Convert the Fraction 3\cfrac { 2 }{ 3 } into an Improper Fraction
a) \cfrac { 11 }{ 3 }
b) \cfrac { 12 }{ 3 }
c) \cfrac { 13 }{ 3 }

Answer

Answer: a) \cfrac { 11 }{ 3 }

Explanation
A combination of Whole Number and a Proper Fraction is called a Mixed Fraction
Here, Mixed Fraction = 3\cfrac { 2 }{ 3 }
Whole Number Part = 3
Numerator = 2
Denominator = 3
Step 1 : Multiply the Whole Number Part and Denominator of the Mixed Fraction
3 x 3 = 9
Step 2 : Add the Numerator to the product obtained in Step 1
2 + 9 = 11
Write the sum as the numerator and denominator would remain the same , as in the Mixed Fraction.
\cfrac { 11 }{ 3 }
Hence, 3\cfrac { 2 }{ 3 } = \cfrac { 11 }{ 3 }


 

Q.4) Solve \cfrac{5}{12} ÷ \cfrac{25}{6}
a) \cfrac{10}{3}
b) \cfrac{3}{10}
c) \cfrac{1}{10}

Answer

Answer: c) \cfrac{1}{10}

Explanation
\cfrac{5}{12} ÷ \cfrac{25}{6}
In order to Divide one fraction by another, we can multiply the first Fraction with the reciprocal of the second Fraction
Reciprocal of second Fraction \cfrac{25}{6} is \cfrac{6}{25}
or we can say \cfrac{5}{12} x \cfrac{6}{25}
Now, on simplifying it
= \cfrac{1}{2} x \cfrac{1}{5}
Multiply all the Numerator together and all the Denominator together.
= \cfrac{1}{10}





Q.5) Find three Fractions Equivalent to \cfrac{11}{6} ?
a) \cfrac{25}{12} , \cfrac{31}{18} , \cfrac{49}{24}
b) \cfrac{44}{9} , \cfrac{35}{16} , \cfrac{43}{24}
c) \cfrac{22}{12} , \cfrac{33}{18} , \cfrac{44}{24}

Answer

Answer: c) \cfrac{22}{12} , \cfrac{33}{18} , \cfrac{44}{24}

Explanation
To get a Fraction equivalent to a given Fraction, we multiply or divide the Numerator and the Denominator of the given Fraction by the same number (except 0 or 1)
Fraction 1 : \cfrac { 11\times 2 }{6\times 2} = \cfrac{22}{12}
Fraction 2 : \cfrac { 11\times 3 }{6\times 3} = \cfrac{33}{18}
Fraction 3 : \cfrac { 11\times 4 }{6\times 4} = \cfrac{44}{24}
Hence, three Equivalent Fractions of \cfrac{11}{6} are \cfrac{22}{12} , \cfrac{33}{18} , \cfrac{44}{24}


 

Q.6) If \cfrac{20}{23} = \cfrac{y}{46}, Then the value of y is ___
a) 40
b) 43
c) 36

Answer

Answer: a) 40

Explanation
Given : \cfrac{20}{23} = \cfrac{y}{46}
On Cross multiplication, we get
20 x 46 = y x 23
920 = 23y
\cfrac{920}{23} = y
40 = y
Or, y = 40
Hence, the missing number is = 40


 

Fractions Worksheets Grade 5

Q.7) Find : \cfrac{15}{7} x \cfrac{21}{60}
a) \cfrac{5}{4}
b) \cfrac{3}{4}
c) \cfrac{6}{5}

Answer

Answer: b) \cfrac{3}{4}

Explanation
\cfrac{15}{7} x \cfrac{21}{60}
To reduce the fraction into its simplest form, we take the HCF of Numerator and Denominator i.e
\cfrac{1}{1} x \cfrac{3}{4}
15 and 60 are divided by the common factor 15 and the Numerator 21 and Denominator 7 are divided by common factor 7 .
The remaining Numerator 3 and the Denominator 4 do not have a common factor and cannot be simplified. so, multiply all the Numerator together and all the Denominator together.
We get, \cfrac{3}{4}


 

Q.8) Write down the Numerator and Denominator of the Fraction: \cfrac{14}{11}
a) Numerator 14 , Denominator 11
b) Numerator 11 , Denominator 14

Answer

Answer: a) Numerator 14 , Denominator 11

Explanation
Numerator is the Upper Number , in the Fraction
So, the Numerator of \cfrac{14}{11} is 14
Denominator is the bottom number in the Fraction
So, the Denominator of \cfrac{14}{11} is 11


 

Q.9) In a class of 60 children, \cfrac{5}{6} are boys. How many boys and girls are there in the class?
a) Number of boys = 45 , Number of girls = 15
b) Number of boys = 50 , Number of girls = 10
c) Number of boys = 55 , Number of girls = 5

Answer

Answer: b) Number of boys = 50 , Number of girls = 10

Explanation
Total number of children in the class = 60
It is given that,
\cfrac{5}{6} of Total number of children in the class = Number of boys
Number of boys = \cfrac{5}{6} x 60
On simplifying it
Number of boys = \cfrac{5}{1} x 10
Number of boys = 50
Number of girls = Total number of children in the class – Number of boys
Number of girls = 60 – 50
Number of girls = 10


 

Q.10) A jar is \cfrac{8}{15} full. The Fraction of the jar that is empty is ?
a) \cfrac{7}{15}
b) \cfrac{8}{15}
c) \cfrac{9}{15}

Answer

Answer: a) \cfrac{7}{15}

Explanation
Part of jar which is full = \cfrac{8}{15}
Since, we don’t know the total part , we assume it to be \cfrac{1}{1} ( in Fraction )
The part of the bucket that is empty = Total part – Filled part
= \cfrac{1}{1}\cfrac{8}{15}
Taking the LCM of 1 and 15 = 15
= \cfrac { 1\times 15-8\times 1 }{ 15 }
= \cfrac{15 - 8}{15}
= \cfrac{7}{15}
Hence, the empty part of the bucket = \cfrac{7}{15}


 

Q.11) Find the difference of \cfrac{7}{3}\cfrac{2}{3} and reduce into its lowest term.
a) \cfrac{5}{3}
b) \cfrac{4}{3}

Answer

Answer: a) \cfrac{5}{3}

Explanation
Difference of Like Fraction = \cfrac { Difference\quad of\quad their\quad Numerators }{ Common\quad Denominator }
= \cfrac{7-2}{3}
= \cfrac{5}{3}
So, the difference of \cfrac{7}{3}and \cfrac{2}{3} is \cfrac{5}{3}


 

Q.12) Find the difference of \cfrac{7}{6} and \cfrac{7}{12} and reduce to its lowest term.
a) \cfrac{7}{12}
b) \cfrac{9}{12}
c) \cfrac{8}{12}

Answer

Answer: a) \cfrac{7}{12}

Explanation
To find the difference of Unlike Fraction
Firstly, we have to change the Unlike Fraction into equivalent Like Fraction, and then subtract the two equivalent Like Fraction
Take LCM of 6 and 12 is 12
Converting the Unlike Fraction into Equivalent Like Fraction
We have to multiply Numerator and Denominator of \cfrac{7}{6} by 2
\cfrac { 7\times 2 }{6\times 2} = \cfrac{14}{12}
We have to multiply Numerator and Denominator of \cfrac{7}{12} by 1
\cfrac { 7\times 1 }{12\times 1} = \cfrac{7}{12}
Now \cfrac{14}{12}\cfrac{7}{12} = \cfrac{7}{12}
Hence, the answer is \cfrac{7}{12}


 

Q.13) Find the sum of \cfrac{1}{15} and \cfrac{8}{15} and reduce to its lowest term.
a) \cfrac{5}{3}
b) \cfrac{4}{5}
c) \cfrac{3}{5}

Answer

Answer: c) \cfrac{3}{5}

Explanation
Sum of Like Fraction = \cfrac { Sum\quad of\quad their\quad Numerators }{ Common\quad Denominator }
= \cfrac{1+8}{15}
= \cfrac{9}{15}
Hence, the sum of \cfrac{1}{15}and \cfrac{8}{15}is \cfrac{9}{15}
Simplifying further,
HCF of 9 and 15 is 3
Dividing both Numerator and Denominator by their HCF i.e,
\cfrac{9 \div 3 }{15 \div 3 } = \cfrac{3}{5}
Hence, the sum of \cfrac{1}{15} and \cfrac{8}{15}= \cfrac{3}{5}


 

Q.14) Find the sum of \cfrac{2}{3} and \cfrac{3}{2} and reduce to its lowest term.
a) \cfrac{13}{6}
b) \cfrac{5}{6}
c) \cfrac{11}{6}

Answer

Answer: a) \cfrac{13}{6}

Explanation
In order to add Unlike Fraction
Firstly, we have to change the Unlike Fraction, into equivalent Like Fractions, and then add the two equivalent Like Fractions
Take LCM of 3 and 2 is 6
Converting the Unlike Fraction into Equivalent Like Fraction
We have to multiply , both the numerator and denominator of \cfrac{2}{3} by 2
\cfrac { 2\times 2 }{3\times 2} = \cfrac{4}{6}
Similarly, we have to multiply , both the numerator and denominator of \cfrac{3}{2}by 3
\cfrac { 3\times 3 }{2\times 3} = \cfrac{9}{6}
Now \cfrac{4}{6}+ \cfrac{9}{6}= \cfrac{13}{6}
Hence, the sum of \cfrac{2}{3} and \cfrac{3}{2}is \cfrac{13}{6}


 

Maths Worksheets for Grade 5

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