Q.1) Compare $\cfrac{11}{3}$ and $\cfrac{5}{3}$
a) $\cfrac{11}{3}$ < $\cfrac{5}{3}$
b) $\cfrac{11}{3}$ > $\cfrac{5}{3}$

Q.2) Convert $\cfrac{59}{10}$ into Mixed Fraction.
a) $5\cfrac{5}{10}$
b) $5\cfrac{7}{10}$
c) $5\cfrac{9}{10}$

Q.3) Convert the Fraction $3\cfrac { 2 }{ 3 }$ into an Improper Fraction
a) $\cfrac { 11 }{ 3 }$
b) $\cfrac { 12 }{ 3 }$
c) $\cfrac { 13 }{ 3 }$

Q.4) Solve $\cfrac{5}{12}$ ÷ $\cfrac{25}{6}$
a) $\cfrac{10}{3}$
b) $\cfrac{3}{10}$
c) $\cfrac{1}{10}$

Q.5) Find three Fractions Equivalent to $\cfrac{11}{6}$ ?
a) $\cfrac{25}{12}$ , $\cfrac{31}{18}$ , $\cfrac{49}{24}$
b) $\cfrac{44}{9}$ , $\cfrac{35}{16}$ , $\cfrac{43}{24}$
c) $\cfrac{22}{12}$ , $\cfrac{33}{18}$ , $\cfrac{44}{24}$

Q.6) If $\cfrac{20}{23}$ = $\cfrac{y}{46}$, Then the value of y is ___
a) 40
b) 43
c) 36

Q.7) Find : $\cfrac{15}{7}$ x $\cfrac{21}{60}$
a) $\cfrac{5}{4}$
b) $\cfrac{3}{4}$
c) $\cfrac{6}{5}$

Q.8) Write down the Numerator and Denominator of the Fraction: $\cfrac{14}{11}$
a) Numerator 14 , Denominator 11
b) Numerator 11 , Denominator 14

Q.9) In a class of 60 children, $\cfrac{5}{6}$ are boys. How many boys and girls are there in the class?
a) Number of boys = 45 , Number of girls = 15
b) Number of boys = 50 , Number of girls = 10
c) Number of boys = 55 , Number of girls = 5

Q.10) A jar is $\cfrac{8}{15}$ full. The Fraction of the jar that is empty is ?
a) $\cfrac{7}{15}$
b) $\cfrac{8}{15}$
c) $\cfrac{9}{15}$

Q.11) Find the difference of $\cfrac{7}{3}$$\cfrac{2}{3}$ and reduce into its lowest term.
a) $\cfrac{5}{3}$
b) $\cfrac{4}{3}$

Q.12) Find the difference of $\cfrac{7}{6}$ and $\cfrac{7}{12}$ and reduce to its lowest term.
a) $\cfrac{7}{12}$
b) $\cfrac{9}{12}$
c) $\cfrac{8}{12}$

Q.13) Find the sum of $\cfrac{1}{15}$ and $\cfrac{8}{15}$ and reduce to its lowest term.
a) $\cfrac{5}{3}$
b) $\cfrac{4}{5}$
c) $\cfrac{3}{5}$

Q.14) Find the sum of $\cfrac{2}{3}$ and $\cfrac{3}{2}$ and reduce to its lowest term.
a) $\cfrac{13}{6}$
b) $\cfrac{5}{6}$
c) $\cfrac{11}{6}$

Q.1) Explanation – Fractions Worksheets Grade 5

On Cross Multiplication $\cfrac{11}{3}$ and $\cfrac{5}{3}$
We multiply 11 x 3 = 33
Similarly, we multiply 3 x 5 = 15
The Fraction whose Numerator has higher value, after multiplication, is greater Fraction
Since, 33 > 15
Hence, $\cfrac{11}{3}$ > $\cfrac{5}{3}$

Correct Answer – b) $\cfrac{11}{3}$ > $\cfrac{5}{3}$

Q.2) Explanation – Fractions Worksheets Grade 5

On dividing 59 by 10
We get, Quotient = 5
Remainder = 9
For a mixed Fraction we have to write Quotient + $\cfrac { Remainder }{ Divisor }$
So, the mixed Fraction is 5 + $\cfrac{9}{10}$ = $5\cfrac{9}{10}$

Correct Answer – c) $5\cfrac{9}{10}$

Q.3) Explanation – Fractions Worksheets Grade 5

A combination of Whole Number and a Proper Fraction is called a Mixed Fraction
Here, Mixed Fraction = $3\cfrac { 2 }{ 3 }$
Whole Number Part = 3
Numerator = 2
Denominator = 3
Step 1 : Multiply the Whole Number Part and Denominator of the Mixed Fraction
3 x 3 = 9
Step 2 : Add the Numerator to the product obtained in Step 1
2 + 9 = 11
Write the sum as the numerator and denominator would remain the same , as in the Mixed Fraction.
$\cfrac { 11 }{ 3 }$
Hence, $3\cfrac { 2 }{ 3 }$ = $\cfrac { 11 }{ 3 }$

Correct Answer – a) $\cfrac { 11 }{ 3 }$

Q.4) Explanation – Fractions Worksheets Grade 5

$\cfrac{5}{12}$ ÷ $\cfrac{25}{6}$
In order to Divide one fraction by another, we can multiply the first Fraction with the reciprocal of the second Fraction
Reciprocal of second Fraction $\cfrac{25}{6}$ is $\cfrac{6}{25}$
or we can say $\cfrac{5}{12}$ x $\cfrac{6}{25}$
Now, on simplifying it
= $\cfrac{1}{2}$ x $\cfrac{1}{5}$
Multiply all the Numerator together and all the Denominator together.
= $\cfrac{1}{10}$

Correct Answer – c) $\cfrac{1}{10}$

Q.5) Explanation – Fractions Worksheets Grade 5

To get a Fraction equivalent to a given Fraction, we multiply or divide the Numerator and the Denominator of the given Fraction by the same number (except 0 or 1)
Fraction 1 : $\cfrac { 11\times 2 }{6\times 2}$ = $\cfrac{22}{12}$
Fraction 2 : $\cfrac { 11\times 3 }{6\times 3}$ = $\cfrac{33}{18}$
Fraction 3 : $\cfrac { 11\times 4 }{6\times 4}$ = $\cfrac{44}{24}$
Hence, three Equivalent Fractions of $\cfrac{11}{6}$ are $\cfrac{22}{12}$ , $\cfrac{33}{18}$ , $\cfrac{44}{24}$

Correct Answer – c) $\cfrac{22}{12}$ , $\cfrac{33}{18}$ , $\cfrac{44}{24}$

Q.6) Explanation – Fractions Worksheets Grade 5

Given : $\cfrac{20}{23}$ = $\cfrac{y}{46}$
On Cross multiplication, we get
20 x 46 = y x 23
920 = 23y
$\cfrac{920}{23}$ = y
40 = y
Or, y = 40
Hence, the missing number is = 40

Q.7) Explanation – Fractions Worksheets Grade 5

$\cfrac{15}{7}$ x $\cfrac{21}{60}$
To reduce the fraction into its simplest form, we take the HCF of Numerator and Denominator i.e
$\cfrac{1}{1}$ x $\cfrac{3}{4}$
15 and 60 are divided by the common factor 15 and the Numerator 21 and Denominator 7 are divided by common factor 7 .
The remaining Numerator 3 and the Denominator 4 do not have a common factor and cannot be simplified. so, multiply all the Numerator together and all the Denominator together.
We get, $\cfrac{3}{4}$

Correct Answer – b) $\cfrac{3}{4}$

Q.8) Explanation – Fractions Worksheets Grade 5

Numerator is the Upper Number , in the Fraction
So, the Numerator of $\cfrac{14}{11}$ is 14
Denominator is the bottom number in the Fraction
So, the Denominator of $\cfrac{14}{11}$ is 11

Correct Answer – a) Numerator 14 , Denominator 11

Q.9) Explanation – Fractions Worksheets Grade 5

Total number of children in the class = 60
It is given that,
$\cfrac{5}{6}$ of Total number of children in the class = Number of boys
Number of boys = $\cfrac{5}{6}$ x 60
On simplifying it
Number of boys = $\cfrac{5}{1}$ x 10
Number of boys = 50
Number of girls = Total number of children in the class – Number of boys
Number of girls = 60 – 50
Number of girls = 10

Correct Answer – b) Number of boys = 50 , Number of girls = 10

Q.10) Explanation – Fractions Worksheets Grade 5

Part of jar which is full = $\cfrac{8}{15}$
Since, we don’t know the total part , we assume it to be $\cfrac{1}{1}$ ( in Fraction )
The part of the bucket that is empty = Total part – Filled part
= $\cfrac{1}{1}$$\cfrac{8}{15}$
Taking the LCM of 1 and 15 = 15
= $\cfrac { 1\times 15-8\times 1 }{ 15 }$
= $\cfrac{15 - 8}{15}$
= $\cfrac{7}{15}$
Hence, the empty part of the bucket = $\cfrac{7}{15}$

Correct Answer – a) $\cfrac{7}{15}$

Q.11) Explanation – Fractions Worksheets Grade 5

Difference of Like Fraction = $\cfrac { Difference\quad of\quad their\quad Numerators }{ Common\quad Denominator }$
= $\cfrac{7-2}{3}$
= $\cfrac{5}{3}$
So, the difference of $\cfrac{7}{3}$and $\cfrac{2}{3}$ is $\cfrac{5}{3}$

Correct Answer – a) $\cfrac{5}{3}$

Q.12) Explanation –

To find the difference of Unlike Fraction
Firstly, we have to change the Unlike Fraction into equivalent Like Fraction, and then subtract the two equivalent Like Fraction
Take LCM of 6 and 12 is 12
Converting the Unlike Fraction into Equivalent Like Fraction
We have to multiply Numerator and Denominator of $\cfrac{7}{6}$ by 2
$\cfrac { 7\times 2 }{6\times 2}$ = $\cfrac{14}{12}$
We have to multiply Numerator and Denominator of $\cfrac{7}{12}$ by 1
$\cfrac { 7\times 1 }{12\times 1}$ = $\cfrac{7}{12}$
Now $\cfrac{14}{12}$$\cfrac{7}{12}$ = $\cfrac{7}{12}$
Hence, the answer is $\cfrac{7}{12}$

Correct Answer – a) $\cfrac{7}{12}$

Q.13) Explanation – Fractions Worksheets Grade 5

Sum of Like Fraction = $\cfrac { Sum\quad of\quad their\quad Numerators }{ Common\quad Denominator }$
= $\cfrac{1+8}{15}$
= $\cfrac{9}{15}$
Hence, the sum of $\cfrac{1}{15}$and $\cfrac{8}{15}$is $\cfrac{9}{15}$
Simplifying further,
HCF of 9 and 15 is 3
Dividing both Numerator and Denominator by their HCF i.e,
$\cfrac{9 \div 3 }{15 \div 3 }$ = $\cfrac{3}{5}$
Hence, the sum of $\cfrac{1}{15}$ and $\cfrac{8}{15}$= $\cfrac{3}{5}$

Correct Answer – c) $\cfrac{3}{5}$

Q.14) Explanation – Fractions Worksheets Grade 5

In order to add Unlike Fraction
Firstly, we have to change the Unlike Fraction, into equivalent Like Fractions, and then add the two equivalent Like Fractions
Take LCM of 3 and 2 is 6
Converting the Unlike Fraction into Equivalent Like Fraction
We have to multiply , both the numerator and denominator of $\cfrac{2}{3}$ by 2
$\cfrac { 2\times 2 }{3\times 2}$ = $\cfrac{4}{6}$
Similarly, we have to multiply , both the numerator and denominator of $\cfrac{3}{2}$by 3
$\cfrac { 3\times 3 }{2\times 3}$ = $\cfrac{9}{6}$
Now $\cfrac{4}{6}$+ $\cfrac{9}{6}$= $\cfrac{13}{6}$
Hence, the sum of $\cfrac{2}{3}$ and $\cfrac{3}{2}$is $\cfrac{13}{6}$

Correct Answer – a) $\cfrac{13}{6}$