Write all the factors of the following numbers (a) 24 (b) 15 (c) 21 (d) 27 (e) 12 (f) 20 (g) 18 (h) 23 (i) 36

Question Write all the factors of the following numbers (a) 24 (b) 15 (c) 21 (d) 27 (e) 12 (f) 20 (g) 18 (h) 23 (i) 36
Board CBSE
Textbook NCERT
Class  Class 6
Subject Maths
Chapter  Chapter 3 Playing with Numbers

Question – Write all the factors of the following numbers (a) 24 (b) 15 (c) 21 (d) 27 (e) 12 (f) 20 (g) 18 (h) 23 (i) 36

Solution –

A factor is a number that divides into another number exactly without leaving any remainder.

(a) We can write 24 as a product of two numbers in following ways i.e.,

24 = 1 Ă— 24

24 = 2 Ă— 12

24 = 3 Ă— 8

24 = 4 Ă— 6

Hence, factors of 24 would be 1, 2, 3, 4, 6, 8, 12 and 24.

(b) We can write 15 as a product of two numbers in following ways i.e.,

15 = 1 Ă— 15

15 = 3 Ă— 5

Hence, factors of 15 would be 1, 3, 5 and 15

(c) We can write 21 as a product of two numbers in following ways i.e.,

21 = 1Ă—21

21 = 3Ă—7

Hence, factors of 21 would be 1, 3, 7 and 21.

(d) We can write 27 as a product of two numbers in following ways i.e.,

27 = 1Ă—27

27 = 3Ă—9

Hence, factors of 27 would be 1, 3, 9 and 27

(e) We can write 12 as a product of two numbers in following ways i.e.,

12 = 1Ă—12

12 = 2Ă—6

12 = 3Ă—4

Hence, factors of 12 would be1, 2, 3, 4, 6 and 12

(f) We can write 20 as a product of two numbers in following ways i.e.,

20 = 1Ă—20

20 = 2Ă—10

20 = 4Ă—5

Hence, factors of 20 would be 1, 2, 4, 5, 10 and 20

(g) We can write 18 as a product of two numbers in following ways i.e.,

18 = 1Ă—18

18 = 2Ă—9

18 = 3Ă—6

Hence, factors of 18 would be 1, 2, 3, 6, 9 and 18

(h) We can write 23 as a product of two numbers in following ways i.e.,

23 = 1Ă—23

Hence, factors of 23 would be 1 and 23

(i)  We can write 36 as a product of two numbers in following ways i.e.,

36 = 1Ă—36

36 = 2Ă—18

36 = 3Ă—12

36 = 4Ă—9

36 = 6Ă—6

Hence, factors of 36 would be 1, 2, 3, 4, 6, 9, 12, 18 and 36

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