Whole Numbers Class 6 MCQ Questions Maths are covered in this Article. Whole Numbers Class 6 MCQ Test contains 12 questions. Answers to MCQs on Whole Numbers Class 6 Maths are available at the end of the last question. These MCQ have been made for Class 6 students to help check the concept you have learnt from detailed classroom sessions and application of your knowledge.
| Board | CBSE |
| Textbook | Maths (NCERT) |
| Class | Class 6 |
| Chapter | Chapter 2 Whole Numbers |
Whole Numbers Class 6 MCQ Questions Maths
1.Find the successor of 85265
(a) 85264
(b) 85266
(c) 85268
(d) 85267
Answer
Answer: (b) 85266
Explanation: The “Successor” of any whole number is the number, obtained by adding 1 to that number.
So, the successor of 85265 is 85265 + 1 = 85266
2. Find the predecessor of 67189 ?
(a) 67187
(b) 67191
(c) 67190
(d) 67188
Answer
Answer: (d) 67188
Explanation:
The “Predecessor” of any whole number is the number obtained by subtracting 1 from it
So, the predecessor of 67189 is 67189 – 1 = 67188
3. In the following pairs of number, state which number will be on right hand side of the whole number line?
( 3457 , 6873 )
(a) 6873
(b) 3457
Answer
Answer: (a) 6873
Explanation:
We know that the smaller number comes on the left and bigger number comes on right on the whole number line.
So between 3457 and 6873
3457 is smaller number
So, 3457 will be on left hand side while 6873 will be on right hand side
3457 < 6873
Hence, 6873 will be on right hand side of the whole number line
4.Find the sum of 6568 + 3548 + 5684 ?
(a) 15801
(b) 15799
(c) 15802
(d) 15800
Answer
Answer: (d) 15800
Explanation:
6568 + ( 3548 + 5684 )
= 6568 + 9232
= 15800
Hence, the sum of 6568 , 3548 and 5684 is 15800
Whole Numbers Class 6 MCQ Questions Maths
5. Find the sum of the following whole numbers 4301 + 998 ?
(a) 5298
(b) 5301
(c) 5300
(d) 5299
Answer
Answer: (d) 5299
Explanation: 4301 + 998
= 4301 + ( 1000 – 2 )
= ( 4301 + 1000 ) – 2
= 5301 – 2
= 5299
Hence, the sum of the given numbers is 5299
6.Find: 5352 x 99
(a) 529848
(b) 529849
(c) 529851
(d) 529850
Answer
Answer: (a) 529848
Explanation: 5352 x ( 100 – 1 )
= ( 5352 x 100 ) – ( 5352 x 1 ) (Here, we use distributive law of multiplication over subtraction )
i.e., a x (b – c) = ( a x b ) – ( a x c )
= 535200 – 5352
= 529848
So, the product of 5352 x 99 is 529848
7. Find the number which when divided by 40 gives 3 as quotient and 1 as remainder
(a) 121
(b) 122
(c) 120
(d) 119
Answer
Answer: (a) 121
Explanation: Given,
Divisor = 40
Quotient = 3
Remainder = 1
In this question we have to use division algorithm
Dividend = (divisor x quotient) + remainder
= ( 40 x 3 ) + 1
= 120 + 1
= 121
Hence, the dividend is 121
8. If the Dividend = 8718 , quotient = 7 and remainder = 3 , find the Divisor ?
(a) 1252
(b) 1245
(c) 1242
(d) 1238
Answer
Answer: (b) 1245
Explanation: Given,
Dividend = 8718
Quotient = 7
Remainder = 3
In this question we have to use division algorithm
Dividend = (divisor x quotient) + remainder
Dividend – remainder = divisor x quotient
Divisor =(8718−3)/7
= (8715)/7 = 1245
Hence, the divisor is 1245
Whole Numbers Class 6 MCQ Questions Maths
9.Find the value of the following:-
( 700 x 42 ) + ( 18 x 700 )
(a) 41991
(b) 42000
(c) 42009
(d) 42007
Answer
Answer: (b) 42000
Explanation: It follows Distributive law of multiplication over addition
Which states that a x (b + c ) = (a x b) + (a x c )
Here, a = 700
b = 42
c = 18
This question is in the form of (a x b) + (a x c )
That is, ( 700 x 42 ) + ( 18 x 700 )
( 700 x 42 ) + ( 700 x 18 ) ( NOTE : Whole number satisfy commutative property under multiplication)
i.e., (a x b) = (b x a)
Here, we have 18 x 700 = 700 x 18
By distributive law, = 700 x ( 42 + 18 )
= 700 x 60
= 42000
10. Solve 16 x ( 7 – 5 ) ?
(a) 33
(b) 32
(c) 31
(d) 34
Answer
Answer: (b) 32
Explanation: Here, we have two method to solve this question
By Distributive law of multiplication over subtraction a x ( b – c ) = (a x b) – (a x c)
here,
a = 16
b = 7
c = 5
1 Method
a x (b – c)
16 x ( 7 – 5 )
= 16 x 2
= 32
2 Method
(a x b) – (a x c)
( 16 X 7 ) – ( 16 x 5 )
= 112 – 80
= 32
11. A person bought 15 chairs on Monday and on the next day he bought 12 chairs If one chair is costing him 45 rupees then how much money he had spend on chairs ?
(a) ₹ 540
(b) ₹ 675
(c) ₹ 1205
(d) ₹ 1215
Answer
Answer: (d) ₹ 1215
Explanation: Total money that he spent = total number of chairs x cost of one chair
= ( 15 + 12 ) x 45
= 27 x 45
= 1215
Total money he spent on chairs is 1215 rupees
12.Write the three whole numbers occurring just after 28239
(a) 28239 , 28240 , 28241
(b) 28238 , 28237 , 28236
(c) 28240 , 28241 , 28242
(d) 28241 , 28242 , 28243
Answer
Answer: (c) 28240 , 28241 , 28242
Explanation: The next three whole number of 28239 can be obtained by adding 1, 2 and 3 to 28239
that is,
28239 + 1 = 28240
28239 + 2 = 28241
28239 + 3 = 28242
Hence the next three whole numbers of 28239 are 28240 , 28241 , 28242 respectively
MCQ Questions for Class 6 Maths with Answers
- Knowing our numbers Class 6 MCQ Questions
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- Basic Geometrical Ideas Class 6 MCQ
- Understanding Elementary Shapes Class 6 MCQ with Answers
- MCQ Questions for Class 6 Maths Integers
- MCQ Questions on Fractions for Class 6
- MCQ on Decimals for Class 6
- Concept of Perimeter and Area Class 6 MCQ
- Algebra Class 6 MCQ Questions
- MCQ on Ratio and Proportion for Class 6
Frequently Asked Questions on Whole Numbers Class 6 MCQ Questions
1. Are these MCQ on Whole Numbers Class 6 are based on 2021-22 CBSE Syllabus?
Yes. There are 12 MCQ’s on this Chapter in this blog.
2. Are you giving all the chapters of Maths Class 6 MCQs with Answers which are given in CBSE syllabus for 2021-22 ?
Yes, we are providing all the chapters of Maths Class 6 MCQs with Answers.