Knowing our numbers Class 6 MCQ Questions

Answer: (a) 34857

Explanation: In order to obtain the number, that comes immediately after a given number, we need to add 1 to the given number.

So, In the present case,

34856 + 1 = 34857

Hence, the number which comes after the given number will be 34857.

Answer: (c) 60722

Explanation: In order to obtain the number, that comes immediately before a given number, we need to subtract 1 from the given number.

So, in the present case,

60723 – 1 = 60722

Hence, the number which comes before the given number is 60722

Answer: (b) 663260

Explanation: The number which comes between two given digits, we have to add 1 to the smaller number . We can also cross-check the answer by subtracting 1 from the greater number.

Case1: 663259 + 1 = 663260

Case 2: 663261 – 1 = 663260

In both the cases, we get the same answer .

Hence, the number which comes between the given numbers is 663260.

Answer: (a) 9753

Explanation: To make the greatest number the first digit should be the greatest among them followed by the digit which is smaller than that and so on. Or we can say we have to arrange the digit in descending order to obtain the greatest number.

In the present case, we can see that 9 is the greatest among them so, first digit will be 9

Next, 7 is greater than 5 and greater than 3 So, 7 will be the next digit.

Now, 5 is greater than 3 so, 5 will be the next digit.

Now, 3 is the smallest among all so, 3 will be the last digit.

Hence, the greatest number formed by using given digit is 9753.

Answer: (b) 7569

Explanation:

In order to get the Compact form of a given number, we have to divide them by their place values

For Thousands place: 7000 ÷ 1000 = 7

For Hundreds Place: 500 ÷ 100 = 5

For Tens Place: 60 ÷ 10 = 6

For Ones Place: 9 ÷ 1 = 9

Hence, the compact form of given number is 7569.

Answer: (c) 5000 + 300 + 50 + 3

Explanation : In expanded form , we write the value of each of the digits, according to its place value

In present case we have,

5 in thousand place

3 in hundred place

5 in tens place

3 in ones place

So, the value of,

= 5 x 1000 = 5000

= 3 x 100 = 300

= 5 x 10 = 50

= 3 x 1 = 3

If we will arrange them according to their place values, we will get, 5000 + 300 + 50 + 3

Hence, Expanded form of 5353 is 5000 + 300 + 50 + 3

Answer: (a) >

Explanation: We compare the numbers one by one, by comparing there place values

In this case,

We will compare the highest place value first In the present case thousand is the highest place value in both the digits . However, thousands place is same that is 8 thousand

Since thousands place is the same, we will compare the hundreds place . However, in both the digits place value of hundreds place are same that is 6 hundred

However, the tens place in 8647 is 4 while in second number 8629 it is 2

Since the Tens place in 8647 > Tens place in 8629

Hence, 8647 > 8629

Answer: (c) 46436< 637573<723635<854362

Explanation: Ascending order is an order in which the smallest number comes first, and is then followed by the number greater than preceding number and so on.

In present case,

First we count the place value for each number :

So, we can see that the smallest number is 46436 which is the only five digit number.

Then, 637573 which is the smallest 6 digit number.

Then, 723635 which is greater than 637573 but less than 854362

Then, 854362 which is the greatest number in all

Hence, the correct ascending order is 46436 < 637573 < 723635 < 854362.

Answer: (b) 735741 > 648684 > 546931 > 454732

Explanation: Descending order is an order in which the greatest number comes first, and is then followed by the number smaller than preceding number and so on.

In present case,

First we find the place value for each number:

So, we can see that the greatest number is 735741 which is the greatest 6-digit number.

Then, 648684 Which is the smaller than 735741 but greater than 546931 and 454732

Then , 546931 Which is smaller than 648684 but greater than 454732

Then, 454732 which is the smallest number in all

Hence, the correct descending order is 735741 > 648684 > 546931 > 454732.

Answer: (c) ₹ 251600

Explanation: If the cost of one article is given, we can calculate the cost of more than one article, by multiplying the cost of one article by the number of article.

In present case,

Cost of 1 table = ₹ 7400

Cost of 34 such tables will be = ₹ (7400 x 34) = ₹ 251600

Hence, the cost of 34 will be ₹ 251600.

Answer: (a) 5

Explanation: If the cost or value of multiple Article are given, and we need to calculate the cost of each Article, then, we can divide the given cost by the number of Articles, to get the cost of 1 Article.

In the present case,

Cost of 11 Articles = ₹ 55

Cost of 1 Article = ₹ (55/11) = ₹ 5

Hence, the Cost of 1 Article is ₹ 5

Answer: (a) 570

Explanation: For rounding off a given digit to the nearest ten. we will first check if the ones digit is greater than or lesser than 5.

If the one’s digit is greater than 5, we will increase tens digit by 1, and replace ones digit by 0.

If one’s digit is lesser than 5, we will replace ones digit by 0, and other digits remain same.

In, present case,

573 has the number 3 in ones place

Since,

3 < 5

Hence, the required rounded number = 570.

Answer: (a) 400

Explanation: In order to round off a given number to the nearest hundred we will first check if the tens digit is greater than or lesser than 5.

If the ten’s digit is greater than 5, we will increase hundreds digit by 1 and replace tens or ones digit by 0.

If the ten’s digit is lesser than 5, we will replace tens and ones digit by 0, and other digits remain same.

In, present case,

We have 434 in which 3 is in tens place and 4 in ones place

We know that 3 < 5

Hence, the required rounded number is 400.

Answer: (c) 6000

Explanation: In order to round off a given number to the nearest thousand we will first check if the hundred digit is greater than or lesser than 5

If the hundred’s digit is greater than 5, we will increase thousands digit by 1 and replace hundreds, tens and ones digit by 0.

If the hundred’s digit is lesser than 5, we will replace hundreds, tens and ones digits by 0, and other digits remain same.

In, present case,

We have 5816 in which 8 is in hundred place , 1 is in tens place and 6 in ones place

So, 8 > 5

Hence, the required estimated number is 6000.

Answer: (b) 140

Explanation: For rounding off a given number to the nearest ten we will first check if the ones digit in that number is greater than or lesser than 5.

If the one’s digit is greater than 5, we will increase tens digit by 1, and replace ones digit by 0.

If one’s digit is lesser than 5, we will replace ones digit by 0, and other digits remain same.

In present case,

44 has the number 4 in ones place

Since,

4 < 5

44 estimated to the nearest ten = 40

97 has the number 7 in ones place Since, 7 > 5

97 estimated to the nearest ten = 100

Therefore,

Estimated sum of 44 and 97 = Estimated value of 44 + Estimated value of 97

= 40 + 100

= 140

Hence, estimation sum is 140.

Answer: (c) 150

Explanation: For rounding off a given number to the nearest ten we will first check if the ones digit in that number is greater than or lesser than 5.

If the one’s digit is greater than 5, we will increase tens digit by 1, and replace ones digit by 0.

If one’s digit is lesser than 5, we will replace ones digit by 0, and other digits remain same.

In present case,

469 has the number 9 in ones place

Since,

9 > 5

469 estimated to the nearest ten = 470

317 has the number 7 in ones place

Since,

7 > 5

317 estimated to the nearest ten = 320

Therefore,

Estimated difference of 469 and 317 = Estimated value of 469 – Estimated value of 317

= 470 – 320

= 150

Hence, estimated difference is 150.

Answer: (a) 11

Explanation: For rounding off a given number to the nearest ten we will first check if the ones digit in that number is greater than or lesser than 5.

If the one’s digit is greater than 5, we will increase tens digit by 1, and replace ones digit by 0.

If one’s digit is lesser than 5, we will replace ones digit by 0, and other digits remain same.

In present case,

453 has the number 3 in ones place

Since,

3 < 5

453 estimated to the nearest ten = 450

43 has the number 3 in ones place

Since,

3 < 5

43 estimated to the nearest ten = 40

Therefore,

Estimated quotient of 453 and 43 = Estimated value of 453 ÷ Estimated value of 43

= 450 ÷ 40

= 11.25

= 11 (approx)

Hence, estimated quotient is 11.

Answer: (b) 12000

Explanation: For rounding off a given number to the nearest hundreds we will first check if the tens digit in that number is greater than or lesser than 5.

If the ten’s digit is greater than 5, we will increase hundreds digit by 1 and replace tens or ones digit by 0.

If the ten’s digit is lesser than 5, we will replace tens or ones digit by 0, and other digits remain same.

In present case,

5675 has the number 7 in tens place

Since,

7 > 5

5675 estimated to the nearest hundred = 5700

6323 has the number 2 in tens place

Since,

2 < 5

6323 estimated to the nearest hundred = 6300

Therefore,

Estimated sum of 5675 and 6323 = Estimated value of 5675 + Estimated value of 6323

= 5700 + 6300

= 12000

Hence, estimation sum is 12000

Answer: (a) 3200

Explanation: For rounding off a given number to the nearest ten we will first check if the ones digit in that number is greater than or lesser than 5.

If the one’s digit is greater than 5, we will increase tens digit by 1, and replace ones digit by 0.

If one’s digit is lesser than 5, we will replace ones digit by 0, and other digits remain same.

In present case,

81 has the number 1 in ones place

Since,

1 < 5

81 estimated to the nearest ten = 80

36 has the number 6 in ones place Since, 6 > 5

36 estimated to the nearest ten = 40

Therefore,

Estimated product of 81 and 36 = Estimated value of 81 x Estimated value of 36

= 80 x 40

= 3200

Hence, estimated product is 3200.

Answer: (b) 5300

Explanation: For rounding off a given number to the nearest hundreds we will first check if the tens digit in that number is greater than or lesser than 5.

If the ten’s digit is greater than 5, we will increase hundreds digit by 1 and replace tens or ones digit by 0.

If the ten’s digit is lesser than 5, we will replace tens or ones digit by 0, and other digits remain same.

In present case,

9876 has the number 7 in tens place

Since,

7 > 5

9876 estimated to the nearest hundred = 9900

4573 has the number 7 in tens place

Since,

7 > 5

4573 estimated to the nearest hundred = 4600

Therefore,

Estimated difference of 9876 and 4573 = Estimated value of 9876 – Estimated value of 4573

= 9900 – 4600

= 5300

Hence, estimation difference is 5300.

Answer: (c) 80000

Explanation: For rounding off a given number to the nearest hundreds we will first check if the tens digit in that number is greater than or lesser than 5.

If the ten’s digit is greater than 5, we will increase hundreds digit by 1 and replace tens or ones digit by 0.

If the ten’s digit is lesser than 5, we will replace tens or ones digit by 0, and other digits remain same.

In present case,

225 has the number 2 in tens place

Since,

2 < 5

225 estimated to the nearest hundred = 200

375 has the number 7 in tens place Since, 7 > 5

375 estimated to the nearest hundred = 400

Therefore,

Estimated product of 225 and 375 = Estimated value of 225 x Estimated value of 375

= 200 x 400

= 80000

Hence, estimation product is 80000.

Answer: (b) 7

Explanation: For rounding off a given number to the nearest hundreds we will first check if the tens digit in that number is greater than or lesser than 5.

If the ten’s digit is greater than 5, we will increase hundreds digit by 1 and replace tens or ones digit by 0.

If the ten’s digit is lesser than 5, we will replace tens or ones digit by 0, and other digits remain same.

In present case,

5646 has the number 4 in tens place

Since,

4 < 5

5646 estimated to the nearest hundred = 5600

792 has the number 9 in tens place Since, 9 > 5

792 estimated to the nearest hundred = 800

Therefore,

Estimated quotient of 5646 and 792 = Estimated value of 5646 ÷ Estimated value of 792

= 5600 ÷ 800

= 7

Hence, estimation quotient is 7.

Answer: (c) 88000

Explanation: For rounding off a given number to the nearest thousands we will first check if the hundreds digit in that number is greater than or lesser than 5.

If the hundred’s digit is greater than 5, we will increase thousands digit by 1 and replace hundreds, tens and ones digit by 0.

If the hundred’s digit is lesser than 5, we will replace hundreds, tens and ones digits by 0, and other digits remain same.

In present case,

53465 has the number 4 in hundreds place

Since,

4 < 5

53465 estimated to the nearest thousand = 53000

34737 has the number 7 in hundreds place Since, 7 > 5

34737 estimated to the nearest thousand = 35000

Therefore,

Estimated sum of 53465 and 34737 = Estimated value of 53465 + Estimated value of 34737

= 53000 + 35000

= 88000

Hence, estimation sum is 88000.

Answer: (a) 19000

Explanation: For rounding off a given number to the nearest thousands we will first check if the hundreds digit in that number is greater than or lesser than 5.

If the hundred’s digit is greater than 5, we will increase thousands digit by 1 and replace hundreds, tens and ones digit by 0.

If the hundred’s digit is lesser than 5, we will replace hundreds, tens and ones digits by 0, and other digits remain same.

In present case,

31310 has the number 3 in hundreds place

Since,

3 < 5

31310 estimated to the nearest thousand = 31000

12312 has the number 3 in hundreds place

Since,

3 < 5

12312 estimated to the nearest thousand = 12000

Therefore,

Estimated difference of 31310 and 12312 = Estimated value of 31310 – Estimated value of 12312

= 31000 – 12000

= 19000

Hence, estimation difference is 19000.

Answer: (c) 25000000

Explanation: For rounding off a given number to the nearest thousands we will first check if the hundreds digit in that number is greater than or lesser than 5.

If the hundred’s digit is greater than 5, we will increase thousands digit by 1 and replace hundreds, tens and ones digit by 0.

If the hundred’s digit is lesser than 5, we will replace hundreds, tens and ones digits by 0, and other digits remain same.

In present case,

4793 has the number 7 in hundreds place

Since,

7 > 5

4793 estimated to the nearest thousand = 5000

5452 has the number 4 in hundreds place

Since,

4 < 5

5452 estimated to the nearest thousand = 5000

Therefore,

Estimated product of 4793 and 5452 = Estimated value of 4793 x Estimated value of 5452

= 5000 x 5000

= 25000000

Hence, estimation product is 25000000.

Answer: (a) CIX

Explanation:

Step I : Express the number in Expanded form.

109 = 100 + 9

Step II : Convert Expanded form of number in Roman Numeral.

i.e.,

100 + 9 = (C) + (IX) = CIX

Hence, 109 would be represented as CIX in Roman Numeral.

Answer: (b) 78

Explanation:

LXXVIII = L + X + X + V + I + I + I

= 50 + 10 + 10 + 5 + 1 + 1 + 1

= 78

Hence, Roman Numeral LXXVIII can be represented as 78 in Hindu Arabic Numeral.