Perimeter And Area Questions For Class 6, deals with various concepts which are as under:-

- Perimeter of Rectangle
- Perimeter of Square
- Perimeter of Triangle
- Perimeter of Equilateral Triangle
- Perimeter of regular pentagon
- Perimeter of regular octagon
- Perimeter of regular decagon
- Area of Rectangle
- Area of Square
- Circumference of a Circle
- Finding Diameter of a circle when circumference is given
- Finding Radius of a circle when circumference is given
- Finding Perimeter of Rectangle when Area & Breadth given
- Finding Perimeter of Rectangle when Area & Length given
- Find the dimensions of a rectangle
- Find the cost of fencing of a rectangular field
- Find the cost of carpeting the room

#### Perimeter And Area Questions For Class 6 – Perimeter of Rectangle

Perimeter of Rectangle is equal to twice of Sum of its length and breadth.

**Perimeter of Rectangle Formula**

Perimeter of Rectangle = 2 ( Length of Rectangle + Breadth of Rectangle )

**Question 1**

Find the perimeter of a rectangle in which:

length = 12 cm and breadth = 5 cm

**Explanation:**

Given:

Length = 12 cm

Breadth = 5 cm

Perimeter of Rectangle = 2 ( l + b ) units

Perimeter of Rectangle = 2 ( 12 + 5 ) cm (Here, Length = 12 cm , Breadth = 5 cm )

Perimeter of Rectangle = ( 2 x 17 ) cm

Perimeter of Rectangle = 34 cm

Hence, Perimeter of Rectangle is 34 cm

#### Perimeter And Area Questions For Class 6 – Perimeter of a Square

Perimeter of a Square is equal to four times of its side.

Perimeter of Square = 4 x Length of each side

**Question 2**

Find the perimeter of a square, each of whose side is 14 cm ?

**Explanation:**

Square is a four sided polygon having all four sides equal in length.

Given:

Side = 14 cm

Perimeter of square = ( 4 x Length of each side ) units

Perimeter of square = ( 4 x 14 ) cm

Perimeter of square = 56 cm

Hence, Perimeter of square is 56 cm

#### Perimeter And Area Questions For Class 6 – Perimeter of Triangle

Perimeter is the sum of all the sides of a closed figure.

Triangle is a three-sided polygon.

Perimeter of a triangle is equal to the sum of all the three sides of the triangle.

Perimeter of Triangle = Sum of its 3 sides

**Question 3**

Find the perimeter of a triangle of sides 11 cm, 5 cm and 8 cm ?

**Explanation**

Given:

Ist side = 11 cm

IInd side = 5 cm

IIIrd side = 8 cm

Perimeter of triangle = Sum of its sides

Perimeter of triangle = ( Ist side + IInd side + IIIrd side ) cm

Perimeter of triangle = ( 11 + 5 + 8 ) cm

Perimeter of triangle = 24 cm

Hence, Perimeter of triangle is 24 cm

#### Perimeter And Area Questions For Class 6 – Perimeter of an Equilateral Triangle

Perimeter is the sum of all the sides of a closed figure.

An equilateral triangle is a triangle having all three sides equal in length.

Perimeter of an equilateral triangle is equal to three times the length of a side of a triangle.

Perimeter of an Equilateral Triangle = 3 x Length of each side

**Question 4**

Find the perimeter of an equilateral triangle of side 9cm

**Explanation**

An equilateral triangle is a triangle having all three sides equal in length.

Length of each side of an equilateral triangle = 9 cm

Perimeter of an equilateral triangle = ( 3 x Length of each side ) units

Perimeter of an equilateral triangle = ( 3 x 9 ) cm

Perimeter of an equilateral triangle = 27 cm

Hence, Perimeter of an equilateral triangle is 27 cm

#### Perimeter And Area Questions For Class 6 – Perimeter of a Regular Pentagon

Perimeter is the sum of all the sides of a closed figure

A regular pentagon is a five-sided polygon.

All the five sides of regular pentagon are equal.

Perimeter of a Regular Pentagon is equal to five times the length its side.

**Perimeter of Regular Pentagon = 5 x Length of each side**

**Question 5**

Find the perimeter of a regular pentagon of side 10cm

**Explanation**

A regular pentagon is a five sided polygon.

All the five sides of regular pentagon are equal.

So, Length of each side of regular pentagon = 10cm

Perimeter of a regular pentagon = ( 5 x Length of each side ) units

= ( 5 x 10 ) cm

= 50 cm

Hence, Perimeter of a regular pentagon is 50 cm

#### Perimeter And Area Questions For Class 6 – Perimeter of a Regular Octagon

Perimeter is the sum of all the sides of a closed figure

A regular octagon is an eight-sided polygon.

All eight sides of regular octagon are equal.

Perimeter of a Regular Octagon is equal to eight times the length its side.

**Perimeter of Regular Octagon = 8 x Length of each side**

**Question 6**

Find the perimeter of a regular octagon of side 10cm

**Explanation**

A regular octagon is an eight sided polygon.

All eight sides of regular octagon are equal.

So, Length of each side of regular octagon =10cm

Perimeter of a regular octagon = ( 8 x Length of each side ) units

= ( 8 x 10 ) cm

= 80 cm

Hence, Perimeter of a regular octagon is 80 cm

#### Perimeter And Area Questions For Class 6 – Perimeter of a Regular Decagon

Perimeter is the sum of all the sides of a closed figure

A regular decagon is a ten-sided polygon whose all ten sides are equal in length.

Perimeter of a Regular Decagon is equal to ten times the length its side.

**Perimeter of Regular Decagon = 10 x Length of each side**

**Question 7**

Find the perimeter of a regular decagon of side 4.5 cm

**Explanation**

A regular decagon is a ten sided polygon that has all ten sides equal in length

Length of a regular decagon =4.5 cm

Perimeter of a regular decagon =(10 x Length of each side)units

=(10 x 4.5) cm

=45 cm

Hence, Perimeter of a regular decagon is 45 cm

#### Perimeter And Area Questions For Class 6 – Area of Rectangle

Area of Rectangle is equal to the product of its length and breadth.

Area of Rectangle = Length x Breadth

**Question 8**

Find the area of rectangle in which: length = 6 cm and breadth = 7 cm

**Explanation**

Given,

length = 6 cm

breadth = 7 cm

Area of rectangle = ( length x breadth )

= ( 6 x 7 ) cm²

= 42 cm²

Hence, the area of rectangle is 42 cm²

#### Perimeter And Area Questions For Class 6 – Finding cost of fencing of a rectangular field

**Question 9**

Find the cost of fencing of a rectangular field 20 m long and 35 m wide at ₹ 6 per metre.

**Explanation**

Length of the field = 20 m

Breadth of the field = 35 m

Perimeter of the field = 2 ( l+b ) units

= 2 ( 20 + 35 ) m

= ( 2 x 55 ) m

= 110 m

Cost of fencing per metre = ₹ 6

Total cost of fencing = ₹ ( 110 x 6 )

= ₹ 660

#### Perimeter And Area Questions For Class 6 – **Finding Length of rope fenced around Rectangular Field**

**Question 10**

The length and the breadth of a rectangular field are 40 m and 60 m respectively. It is fenced with 2 round of rope. Find the length of the rope.

**Explanation**

Length of the field = 40 m

Breadth of the field = 60 m

Perimeter of the field = 2 (l+b) units

= 2 ( 40 + 60 ) m

= ( 2 x 100 ) m

= 200 m

Total length of rope = 2 x Perimeter of the field

= ( 2 x 200 ) m

= 400 m

#### Perimeter And Area Questions For Class 6 – **Area of Square**

Area of Square is equal to (length of its side x length of side).

Area of Square = ( side x side ) = (side)²

**Question 11**

Find the area of a square plot of side 2.5 cm

**Explanation**

Sides of square = 2.5 cm

Area of square = ( side x side ) cm²

= ( 2.5 x 2.5 ) cm²

= 6.25 cm²

Hence, the area of square plot is 6.25 cm²

#### Perimeter And Area Questions For Class 6 – Finding Circumference of the circle when radius is given

Circumference of a circle is the measure of the length of the circle.

Circumference of a circle = 2πr

**Question 12**

Find the circumference of a circle of radius 49 cm?

**Explanation**

The radius of given circle is r = 49 cm

Circumference of the circle = 2πr

= ( 2 x 22/7 x 49 ) cm

= 308 cm

Hence, the circumference of the given circle is 308 cm

#### Perimeter And Area Questions For Class 6 – Finding Circumference of the circle when diameter is given

Circumference of a circle is the measure of the length of the circle.

Circumference of a circle = 2πr

**Question 13**

Find the circumference of a circle, whose diameter is 56 cm?

**Explanation**

The diameter of given circle = 56 cm

Circumference of circle = 2πr

= ( 2 x 22/7 x 28 ) cm

= 176 cm

Hence, the circumference of the given circle is 176 cm

#### Perimeter And Area Questions For Class 6 – Radius of a Circle

**Question 14**

Find the radius of the circle whose circumference is 132 cm?

**Explanation**

Let, the radius of the given circle be r cm

As we know that,

Circumference of the circle = 2πr cm

Given,

Circumference of a circle = 132cm

2πr = 132 (from above)

= 21cm

Hence, the radius of the circle = 21cm

#### Perimeter And Area Questions For Class 6 – Finding Diameter of a circle when circumference is given

**Question 15**

Find the diameter of the circle whose circumference is 264 cm?

**Explanation**

Let, the radius of the given circle be r cm

As we know that,

Circumference of the circle = 2πr cm

Given,

Circumference of a cicle = 264cm

Therefore,

2πr = 264 (from above)

= 42cm

Diameter of the circle = 2r

= (2 x 42)cm

= 84cm

Hence, the Diameter of the circle is 84 cm

#### Perimeter And Area Questions For Class 6 – Problem-based on circumference of a circle

**Question 16**

The diameter of a wheel of a car is 42 cm. Find the distance covered by the car during the time in which the wheel makes 1600 revolutions?

**Explanation**

Radius of the wheel = 42/2 cm = 21 cm

Circumference of the wheel = 2πr

= 132 cm

= 1.32 m ( As we know that, 1 m = 100 cm )

Distance covered by wheel in 1 revolution = Circumference of the wheel

Distance covered by wheel in 1 revolution = 1.32 m

Distance covered by wheel in 1600 revolutions = ( 1.32 x 1600 ) m

= 2112 m

= 2.112 km ( As we know that, 1 m = 1000 km )

Hence, Distance covered by wheel in 1600 revolutions is 2.112 km

#### Perimeter And Area Questions For Class 6 – Finding Perimeter of Rectangle when Area & Breadth is given

**Question 17**

The area of a rectangle is 832 cm² and its breadth is 26 cm. Find the perimeter of the rectangle.

**Explanation**

Given

Area = 832 cm²

breadth = 26 cm

Perimeter of the rectangle = 2 x ( l + b ) cm

= 2 x ( 26 + 32 ) cm

= ( 2 x 58 ) cm

= 116 cm

Hence, the perimeter of the rectangle is 116 cm

#### Perimeter And Area Questions For Class 6 – Finding Perimeter of Rectangle when Area & Length are given

**Question 18**

The area of a rectangle is 85 cm² and its length is 5 cm . Find the perimeter of the rectangle.

**Explanation**

Given

Area = 85 cm²

length = 5 cm

Perimeter of the rectangle = 2 x ( l + b ) cm

= 2 x ( 5 + 17 ) cm

= ( 2 x 22 ) cm

= 44 cm

Hence, perimeter of the rectangle is 44 cm

#### Perimeter And Area Questions For Class 6 – Problem based on Perimeter of rectangle

**Question 19**

The length and the breadth of a rectangle are in the ratio 2 : 5 . If its perimeter is 28 m , find its dimensions.

**Explanation**

Let, length and breadth be 2y m and 5y m

Since, perimeter of rectangle = 2 (l+b) units

= 2 ( 2 y + 5 y ) m

= ( 2 x 7 y ) m

= 14ym

But, perimeter of rectangle = 28 m

Since, 14 y = 28

y = 28/14

y = 2

So, length = ( 2 x 2 ) m = 4 m

breadth = ( 5 x 2 ) m = 10 m

#### Perimeter And Area Questions For Class 6 – Problem based on cost of carpeting the room

**Question 20**

A room is 48 m long and 18 m broad. Find the cost of carpeting the room with a carpet of width 18 m at the rate of ₹ 50 per metre.

**Explanation**

Length of the room = 48 m

Breadth of the room = 18 m

Area of the floor of the room = ( 48 x 18 ) m²

= 864 m²

Area of carpet required = 864 m²

Rate of carpeting = 50 per metre.

Cost of carpeting = ₹ ( 48 x 50 ) = ₹ 2400