Pair of Linear Equations in Two Variables Class 10 MCQ with Answers are covered in this Article. Pair of Linear Equations in Two Variables Class 10 MCQ Test contains 25 questions. Answers to MCQs on Pair of Linear Equations in Two Variables Class 10 Maths are available after clicking on the answer. MCQ Questions for Class 10 Maths with Answers have been made for Class 10 students to help check the concept you have learnt from detailed classroom sessions and application of your knowledge.
Board | CBSE |
Textbook | Maths (NCERT) |
Class | Class 10 |
Chapter | Chapter 3 Pair of Linear Equations in Two Variables |
Category | MCQ Questions for Class 10 Maths with Answers |
Pair of Linear Equations in Two Variables Class 10 MCQ with Answers
1. A pair of linear equation a1 x+ yb1+ c1=0, a2 x+ b2y+ c2=0, is said to consistent, if
(a) a1 /a2 ≠b1 /b2
(b) a1 /a2= b1 /b2
(c) a1 /a2 = b1 /b2 ≠c1 /c2
(d) None
Answer
Answer: (a) a1 /a2 ≠b1 /b2
Explanation : If a1 /a2 ≠b1 /b2, then the pair of linear equations is consistent.
2. A pair of linear equations which has no solution, is called
(a)consistent
(b) Inconsistent
(c) dependent and consistent
(d) dependent and inconsistent
Answer
Answer: (b) Inconsistent
Explanation: A pair of linear equations which has no solution, is called an inconsistent pair of linear equations.
3. 9√5 x -√3 y = 10 and 9√5 x – √27 y =0, then value of x and y is
(a)x=√5/3 , y = 5√3/3
(b) x =5√3/3  , y = √3/3
(c) x =5√5/3  and y = 5/3
(d) None of these
Answer
Answer: (a)x=√5/3 , y = 5√3/3
Explanation: 9√5x -√3 y = 10
9√5x -10=√3 y
and y = (9√5x -10)/(√3)
Substituting value of y in 9√5x -√27 y =0
9√5x -√27((9√5x -10)/(√3)) =0
9√5x -3√3((9√5x -10)/(√3)) =0
9√5x – 27√5x + 30 =0
18√5x = 30
x = 30/(18√5) = (√5)/3
and y = (9√5x -10)/(√3)
= (9√5(√5/3) -10)/(√3)
= (15 -10)/(√3)
= 5/(√3) = (5√3)/3
4. Â If in the equation 5x+2y=7 the value of x is 1, then value of y is
(a)-1
(b)0
(c)1
(d)2
Answer
Answer: (c)1
Explanation: 5x+2y=7
Substitute the value of x=1 in above equation
5×1+2y=7
2y=7-5
2y=2
y=1
5. If x+y=4 and x-y=10, then value of x and y is
(a) 7, -3
(b) -3,7
(c) 7,3
(d) 3,7
Answer
Answer: (a) 7, -3
Explanation: x+y=4 ……………………………………………(1)
x-y=10……………………………………………..(2)
Add equation (1) and (2)
2x = 14
x = 7
Substitute value of x in equation (1)
7+y=4
y = -3
6. If 3x+4y=12 and 3x+4y =17, then lines are
(a) parallel
(b) intersecting
(c)coincident
(d) All of the above
Answer
Answer: (a) parallel
Explanation:
a1 = 3, b1=4 and c1=-12
a2=3, b2-=4 and c2=-17
On comparing ratios, we get
a1 /a2 = b1 /b2 ≠c1 /c2
So, the lines are parallel.
Pair of Linear Equations in Two Variables Class 10 MCQ with Answers
7. The sum of two numbers is 50 and one number is four times the other. The numbers are
(a) 35,15
(b) 40,20
(c) 25,25
(d) 10,40
Answer
Answer: (d) 10,40
Explanation: Let the first number be x.
And the second number be 4x.
According to question,
x+4x=50
5x=50
x=10
So, the first number is 10 and second number is 40
8. The pair of equations 9m+10n+11=0 and 18m+20n+33=0 have
(a) a unique solution
(b)exactly two solutions
(c) no solution
(d)infinitely many solutions
Answer
Answer: (c) no solution
Explanation: Given equations are 9m+10n+11=0 and 18m+20n+33=0
Comparing with standard form
a1 = 9, b1=10 and c1=11
a2=18, b2-=20 and c2=33
a1/a2 = 9/18 = 1/2 , b1/b2Â = 10/20 = 1/2, c1/c2Â = 11/33 = 1/3
a1 /a2 = b1 /b2 ≠c1 /c2
So, the pair of equations has no solution.
9. If the pair of linear equations has no solution, then the lines representing these equations will
(a)coincide
(b)intersect at one point
(c)parallel to each other
(d) parallel to y-axis
Answer
Answer: (c)parallel to each other
Explanation: If the pair of linear equations has no solution, then the lines representing these equations will be parallel to each other.
10. A pair of linear equations which has a unique solution x=1 and y=-2 is
(a) x+y =1; 2x+3y=-6
(b) x+2y=9; 3x+7y=0
(c) 2x+2y=-2; 7x-8y=23
(d) x+4y=0; 4y+3x=1
Answer
Answer: (c) 2x+2y=-2; 7x-8y=23
Explanation: If x=1 and y=-2 is unique solution of any pair of equations, then these values must satisfy that pair of equations.
Now, 2x+2y = -2
LHS = 2x+2y = 2(1) +2(-2) =2-4 = -2 = RHS
LHS = 7x-8y = 7(1)-8(-2) = 7+16 = 23 = RHS
11. Â If the lines 3x+4(k+1)y+4=0 and 2x+8y+12=0 are parallel then, value of k is
(a)1
(b)2
(c)3
(d)4
Answer
Answer: (b)2
Explanation: The condition for parallel lines is
a1 /a2 = b1 /b2 ≠c1 /c2
3/2 = (4(k+1))/8
3=(k+1)
K=2
12.  If 3x+7y=10 and 6y-3x=16, then what will be the value of ‘m’ in y = mx+3
(a)4/3
(b)-4/3
(c)3/4
(d) -3/4
Answer
Answer: (c)3/4
Explanation: Given equations are 3x+7y=10…………..(1)
and 6y-3x=16………………..(2)
Add equation (1) and (2)
3x+7y+ 6y-3x=16+10
13y=26
y = 2
Substitute value of y in equation (1)
3x+7(2) = 10
3x=-4
x = -4/3
Now, y = mx+3…………………………(3)
Substitute values of x and y in equation (3)
2 = m (-4/3) +3
2= (-4m+9)/3
-4m+9 = 6
-4m=-3
m = 3/4
13. Graphically, the pair of equations 2x+4y=12 and x+2y=8 represents two lines which are
(a)intersecting at one point
(b)parallel
(c)intersecting at two points
(d)coincident
Answer
Answer: (b)parallel
Explanation: 2x+4y=12
X | 0 | 6 |
Y | 3 | 0 |
x+2y=8
X | 8 | 0 |
Y | 0 | 4 |
14. The graph of y=x is a line
(a)Parallel to x-axis
(b)parallel to y axis
(c) Passing through the origin
(d) perpendicular to x-axis
Answer
Answer: (c) Passing through the origin
Explanation: y=x
X | 0 | 1 | 2 | -1 |
Y | 0 | 1 | 2 | -1 |
15. Rohan bought some mobile and watch for his shop. The number of watches are 2 more than 6 times of mobile also number of watches are 5 more than 3 times pf mobile. Then number of mobile and watches will be
(a)(1,8)
(b)(8,1)
(c) (1,1)
(d) (8,8)
Answer
Answer: (a)(1,8)
Explanation: Let number of mobiles be x and number of watches be y.
According to question
y = 6x + 2
y = 3x + 5
X | 0 | -1/3 |
y = 6x +2 | 2 | 0 |
X | 0 | -5/3 |
y = 3x+5 | 5 | 0 |
From the above graph we can observe that both lines are intersecting at point (1,8).
So, number of mobiles is 1 and number of watches is 8
Pair of Linear Equations in Two Variables Class 10 MCQ with Answers
16. Check the equation x+5y=10 and 0.4x-2y =4 is consistent or inconsistent
(a)Consistent
(b)Inconsistent
Answer
Answer: (a)Consistent
Explanation: x+5y=10
X | 0 | 10 |
y = (10-x)/5 | 2 | 0 |
0.4x-2y =4 or 4x-20y =40 or x-5y = 10
X | 0 | 10 |
y = (x-10)/5 | -2 | 0 |
So, from the above graph we can observe that there is point which is common to both lines. So, solution of the pair of equations is x = 10 and y = 0 i.e., the pair of linear equations is consistent.
17. For what value of k, do the equations 7x+14y=21 and 14x-2ky=42 represent coincident lines
(a)-14
(b)14
(c) 11
(d)7
Answer
Answer: (a)-14
Explanation: For coincident lines,
a1 /a2 = b1 /b2 = c1 /c2
7/14=14/(-2k)=21/42
1/2=7/(-k)
k = -14
18. Â If in the equation 0.75x+0.25y=9, the value of x is 1, then what will be the value of y
(a)25
(b)33
(c)11
(d)25.05
Answer
Answer: (b)33
Explanation: 0.75x+0.25y=9
Substitute x=1
0.75(1)+0.25y=9
0.25y=9-0.75
0.25y = 8.25
y = 33
19. Solution of equations 2/x – 5/y = 10 and 1/x + 3/y = -5 is
(a) (5/11 , -20/11 )
(b) (11/5 ,-11/20 )
(c) (-20/11, 5/11 )
(d) ( 5/11, 1/11)
Answer
Answer: (b) (11/5 ,-11/20 )
Explanation: 2(1/x) –5( 1/y) = 10 and 1(1/x) +3 ( 1/y) = -5
Let 1/x = p and 1/y = q
Then, 2p-5q = 10………. (1)
and p + 3q =-5
p = -5-3q
Put value of p in equation (1)
2(-5-3q) – 5q =10
-10-6q – 5q =10
-11q = 20
q = -20/11
p = -5 -3(-20/11)= -5 + 60/11
p = (-55+60)/11 = 5/11
Now, p = 1/x= 5/11
x = 11/5
and q = 1/y=(-20)/11
y = (-11)/20
20. Which of the following is not a solution of 3x+y=9
(a) (2,3)
(b) (1.2,5.4)
(c) (3,3)
(d) (1,6)
Answer
Answer: (c) (3,3)
Explanation: For (3,3)
LHS = 3(3)+3 = 9+3 = 12 ≠RHS
21. Find the value of p for which the system of equations px+7y=20 and x-y=2 will represent intersecting lines
(a)p ≠-7
(b)p=-7
(c)p=7
(d) p
Answer
Answer: (a)p ≠-7
Explanation: The condition for intersecting lines is
a1 /a2 ≠b1 /b2
p/1 ≠7/(-1)
P ≠-7
Pair of Linear Equations in Two Variables Class 10 MCQ with Answers
22. Find the solution of the following pair of linear equation: 2x- √3 y = 6 and x-y=8
(a) ((-6+√3)/2, (10+√3)/2 )
(b) ((-2+√3)/2, (-6+√3)/2)
(c) ((2+√3)/2, (-2+√3)/2 )
(d) ((6+√3)/2, (-10+√3)/2 )
Answer
Answer: (d) ((6+√3)/2, (-10+√3)/2 )
Explanation: For given equations 2x-√3 = 6 and x-y=8
x = (6+√3 )/2
Substitute x = (6+√3 )/2
(6+√3 )/2-y=8
6+√3 – 2 y = 16
6+√3-16 = 2y
y = (-10+√3 )/2
23. Â The cost of 2 dolls and 5 cars is Rs9 and the cost of 4 dolls and 8 cars is Rs 16. Find the cost of each doll and each car.
(a)(1,3)
(b)(2,1)
(c)(2,4)
(d)(4,3)
Answer
Answer: (b)(2,1)
Explanation: Let cost of a doll is Rs x and cost of a car is Rs y
According to question
2x+5y=9……………….(1)
4x+8y=16……………….(2)
x + 2y = 4
x = 4-2y…………….(3)
Substitute x in equation (1)
2(4-2y) + 5y = 9
8-4y+5y = 9
y = 1
substitute value of y in equation (3)
x = 4-2(1)
x=2
Cost of a doll is Rs 2 and cost of a car is Rs1.
24. Find the value of p, if 2x+py=7 and px+12y=21 are coincident lines
(a)p=8√2
(b)p=2√3
(c)p=3
(d)p=2√6
Answer
Answer: (d)p=2√6
Explanation: The condition for coincident lines is
a1 /a2 = b1 /b2 = c1 /c2
2/p=p/12
P² =24
p = 2√6
25. Solution of equations 2/(x-10) – 1/(y-2) = 10 and 1/(x-10) +2/(y-2) = 15 is
(a) (71/7, 9/4 )
(b) (7/71 , 4/9 )
(c) (7,4)
(d) (4,7)
Answer
Answer: (a) (71/7, 9/4 )
Explanation: 2(1/(x-10)) – 1/(y-2) = 10 and 1/(x-10) + 2(1/(y-2)) = 15
Let (1/(x-10)) = p and (1/(y-2)) = q
Now, 2p -q = 10
q = 2p – 10
p + 2q = 15
Substituting value of q
p + 2(2p – 10) = 15
p + 4p -20 =15
5p = 35 and p = 7
q = 2(7) – 10 = 4
Now, p = (1/(x-10)) = 7
1 = 7x -70
7x = 71 and x =71/7
q = (1/(y-2)) = 4
1 = 4y – 8
4y = 9 and y = 9/4
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