NCERT Solutions for Class 8 Maths Chapter 9 Exercise 9.2 Algebraic Expressions & Identities

NCERT Solutions for Class 8 Maths Chapter 9 Exercise 9.1 Algebraic Expressions & Identities

ncert solutions for class 8 maths chapter 9 exercise 9.2 contains 4 questions and each question has explained in detail and stepwise. If you are class 8th student and currently preparing chapter 9 exercise 9.2 then you must be looking for the maths class 8 chapter 9 exercise 9.2 solution for your exams preparation. Here we are providing complete solutions for class 8 maths exercise 9.2.

Table of Content

Category	NCERT Solutions Class 8
Subject	Maths
Chapter	Chapter 9
Exercise	Exercise 9.2
Chapter Name	Algebraic Expressions & Identities

NCERT Solutions for Class 8 Maths Chapter 9 Exercise 9.2 Algebraic Expressions & Identities, has been designed by the NCERT to test the knowledge of the student on the following topics.

• Multiplication of Algebraic Expressions: Introduction
• Multiplying a Monomial by a Monomial
  – Multiplying two monomials
  – Multiplying three or more monomials

Maths Class 8 Chapter 9 Exercise 9.2 Question Answers

Q.1 Find the product of the following pairs of monomials.

(i) 4, 7p
(ii) − 4p, 7p
(iii) − 4p, 7pq
(iv) 4p³, − 3p
(v) 4p, 0

Solution:

The product of pair of monomials:

Q.2 Find the areas of rectangles with the following pairs of monomials as their lengths and breadths respectively.

(p,q); (10m, 5n); (20x², 5y²); (4x, 3x²); (3mn, 4np)

Solution:

We know that, Area of rectangle = length × breadth

Area of rectangle with length p and breadth q

= p × q = pq

Area of rectangle with length 10m and breadth 5n

= 10m × 5n = 10 × 5 × m × n = 50 mn

Area of rectangle with length 20x² and breadth 5y²

= 20x² × 5y² = 20 × 5 × x² × y² = 100 x²y²

Area of rectangle with length 4x and breadth 3x²

= 4x × 3x² = 4 × 3 × x × x² = 12x³

Area of rectangle with length 3mn and breadth 4np

= 3mn × 4np = 3 × 4 × m × n × n × p = 12mn²p

Q.3 Complete the table of products.

Solution:

Q.4 Obtain the volume of rectangular boxes with the following length, breadth and height respectively

(i) 5a, 3a², 7a⁴
(ii) 2p, 4q, 8r
(iii) xy, 2x²y, 2xy²
(iv) a, 2b, 3c

Solution:

We know that, Volume = Length × Breadth × Height

(i) Volume of rectangular box with length 5a, breadth 3a² and height 7a⁴

= 5a × 3a² × 7a⁴ = 5 × 3 × 7 × a × a² × a⁴ = 105 a⁷

(ii) Volume of rectangular box with length 2p, breadth 4q and height 8r

= 2p × 4q × 8r = 2 × 4 × 8 × p × q × r = 64pqr

(iii) Volume of rectangular box with length xy, breadth 2x²y and height 2xy²

= xy × 2x²y × 2xy² = 2 × 2 × xy × x²y × xy² = 4x⁴y⁴

(iv) Volume of rectangular box with length a, breadth 2b and height 3c

= a × 2b × 3c = 2 × 3 × a × b × c = 6abc

Q.5 Obtain the product of 

(i) xy, yz, zx
(ii) a, − a², a³
(iii) 2, 4y, 8y², 16y³
(iv) a, 2b, 3c, 6abc
(v) m, − mn, mnp

Solution:

Other Exercise’s NCERT solutions for class 8 maths chapter 9

• Exercise 9.1 – Algebraic Expressions and Identities
• Exercise 9.2 – Algebraic Expressions and Identities
• Exercise 9.3 – Algebraic Expressions and Identities
• Exercise 9.4 – Algebraic Expressions and Identities
• Exercise 9.5 – Algebraic Expressions and Identities

The next Exercise for NCERT Solutions for Class 8 Maths Chapter 9 Exercise 9.3 Algebraic Expressions and Identities can be accessed by clicking here

• Maths – NCERT Solutions Class 8
• NCERT Solutions Class 8

NCERT Solutions For Class 8 Maths Chapter 9 Exercise 9.2 Algebraic Expressions & Identities