**Download NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.5**

**NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.5 – Linear Equation in one variable, has been designed by the NCERT to test the knowledge of the student on the topic – Reducing Equations to Simpler Form**

**Solve the following linear equations.**

**1. –=+**

**Solution:**

–=+

=

=

x=

x=

x=

**2. –+=21**

**Solution:**

Multiply both LHS and RHS with LCM of 2,4 and 6 = 12

12×=12×21

6n-9n+10n=252

16n-9n=252

7n=252

n=36

**3. x+7-=–**

**Solution:**

Multiply both LHS and RHS with LCM of 2,3 and 6 = 6

6×(x+7-)=6×(–)

6x+42-16x=17-15x

-10x+42=17-15x

15x-10x=17-42

5x=-25

x=-5

**4. =**

**Solution:**

5×(x-5)=3×(x-3)

5x-25=3x-9

5x-3x=25-9

2x=16

x=8

**5. –=-t**

**Solution:**

(3×(3t-2)-4×(2t+3)+12t)=12×

9t-6-8t-12+12t=8

13t-18=8

13t=26

t=2

**6. m-=1-**

**Solution:**

= 1

6×m-3×(m-1)+2×(m-2)=6

6m-3m+3+2m-4=6

5m-1=6

5m=7

m=

**Simplify and solve the following linear equations**

**7. 3(t-3)=5(2t+1)**

**Solution:**

3t-9=10t+5 (Opening the brackets)

10t-3t=-9-5

7t=-14

t=-2

**8. 15(y-4)-2(y-9)+5(y+6)=0**

Solution:

15y-15×4-2y+2×9+5y+5×6=0

15y-60-2y+18+5y+30=0

18y-12=0

y==

**9. 3(5z-7)-2(9z-11)=4(8z-13)-17**

**Solution:**

3×5z-3×7-2×9z+2×11=4×8z-4×13-17 (Opening the brackets)

15z-21-18z+22=32z-52-17

-3z+1=32z-69

32z+3z=69+1

35z=70

z=2

**10. 0.25(4f-3)=0.05(10f-9)**

**Solution:**

0.25×4f-3×0.25=0.05×10f-0.05×9

1f-0.75=0.5f-0.45

f-0.5f=0.75-0.45

0.5f=0.3

f===0.6

**The next Exercise for** **NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.6 – Linear Equation in one variable can be accessed by clicking here**

**Download NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.5**

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