NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.3 – Linear Equation in one variable, has been designed by the NCERT to test the knowledge of the student on the topic – Solving Equations having the Variable on both Sides

### NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.3

**NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.3**

**Solve the following and check your results.**

**1. 3x=2x+18**

**Solution: **3x-2x=18

x=18

**To check:**3x=2x+18

3×(18)=2×(18)+18

54=36+18

54=54

LHS = RHS

Hence, x=18 is the correct solution

**2. 5t-3=3t-5**

**Solution:**

5t-3t=3-5

2t=-2

t=-(2/2)

t=-1

**To check:** 5t-3=3t-5

5×(-1)-3=3×(-1)-5

-5-3=-3-5

-8=-8

LHS = RHS

Hence, t=-1 is the correct solution

**3. 5x+9=5+3x**

**Solution:**

5x-3x=5-9

2x=-4

x=-(4/2)

x=-2

**To check:** 5x+9=5+3x

5×(-2)+9=5+3×(-2)

-10+9=5+(-6)

-1=-1

LHS = RHS

Hence, x=-2 is the correct solution

**4. 4z+3=6+2z**

**Solution:**

4z – 2z = 6 – 3

2z = 3

z = (3/2)

**To check:** 4z+3=6+2z

4 × (3/2) + 3 = 6 + 2x(3/2)

6 + 3 = 6 + 3

9 = 9

LHS = RHS

Hence, z = (3/2) is the correct solution

**5. 2x-1=14-x**

**Solution:**

2x+x=14+1

3x=15

x=(15/3)

x=5

**To check:** 2x-1=14-x

2×(5)-1=14-(5)

10-1=14-5

9=9

LHS = RHS

Hence, x=5 is the correct solution

**6. 8x+4=3 (x-1)+7**

**Solution:**

8x+4=3x-3+7

8x+4=3x+4

8x-3x=0

5x=0

x=0

**To check:** 8x+4=3 (x-1)+7

8×0+4=3 (0-1)+7

4=-3+7

4=4

LHS = RHS

Hence, x=0 is the correct solution

**7. x=(4/5)(x+10)**

**Solution:**

5x=4(x+10)

5x=4x+40

5x-4x=40

x=40

**To check:** x=(4/5)(x+10)

40=(4/5)(40+10)

40=(4/5) (50)

40=40

LHS = RHS

Hence, x=40 is the correct solution

**8. (2x/3)+1 = (7x/15)+3**

**Solution:**

(2x/3) – (7x/15) = 3-1

(3x/15) = 2

x=(2 × 15)/3

x=(30/3)

x=10

**To check:** (2x/3)+1=(7x/15)+3

(2 × 10)/3+1=(7 × 10)/15+3

(20/3)+1=(70/15)+3

(23/3)=(115)/15

(23/3) = (23)/3

LHS = RHS

Hence, x=10 is the correct solution

**9. 2y + (5/3) = (26/3) – y**

**Solution:**

2y + y = (26/3) – (5/3)

3y = (26-5)/3

3y = (21/3)

3y=7

y=(7/3)

**To check:** 2y+(5/3)=(26/3)-y

2×(7/3)+(5/3)=(26/3)-(7/3)

(14/3)+(5/3)=(19/3)

(19/3) = (19/3)

LHS = RHS

Hence, y=(7/3) is the correct solution

**10. 3m=5m-(8/5)**

**Solution:**

5m-3m=(8/5)

2m=(8/5)

m= (8/5×2)

m = 8/10 = 4/5

m = 4/5

**To check:** 3m = 5m – (8/5)

3×(4/5)=5×(4/5)-(8/5)

(12/5)=(20/5)-(8/5)

(12/5)=(12/5)

LHS = RHS

Hence, m=(4/5) is the correct solution

**The next Exercise for** **NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.4 – Linear Equation in one variable can be accessed by clicking here**

**Download NCERT Solutions for Class 8 Maths Chapter 2 Exercise 2.3**

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