Integers Questions For Class 6

Integers Questions For Class 6, deals with various concepts which are as under:-

• Successor of an Integers
• Predecessor of an Integers
• Addition of Integers
• Subtracting Integers
• Multiplication of Integers
• Dividing Integers

Integers Questions For Class 6 – Successor of an Integers

The successor of any number (including Integers ) will be the number which is 1 greater than the number, or comes after that number in number line.

Example 1

The successor of given integer 639 is ?

The successor of any number (including Integers ) will be the number which is 1 greater than the number, or comes after that number in number line

So, we have to add 1 to the integer to find its successor.

In present case,

639 + 1 = 640

So, the successor of 639 is 640

Example 2

The successor of given integer -538 is ?

The successor of any number (including Integers ) will be the number which is 1 greater than the number, or comes after that number in number line

So, we have to add 1 to the integer to find its successor.

In present case,

-538 + 1 = -537

So, the successor of -538 is -537

Integers Questions For Class 6 – Predecessor of an Integers

The predecessor of any number (including integers) will be the number which is one lesser than the number, or comes before than that number in number line

Example 3

The predecessor of given integer 1639 ?

The predecessor of any number (including integers) will be the number which is one lesser than the number, or comes before than that number in number line

So, we have to subtract 1 from the given integer to find its predecessor.

1639 – 1 = 1638

So, the predecessor of 1639 is 1638

Example 4

The predecessor of given integer -582 ?

The predecessor of any number (including integers) will be the number which is one lesser than the number, or comes before than that number in number line

So, we have to subtract 1 from the given integer to find its predecessor.

-582 – 1 = -583

So, the predecessor of -552 is -583

Integers Questions For Class 6 – Addition of Integers

Rule 1 – While adding two integers with the same sign, we add their values regardless of their signs, and give the sum, their common sign.

Rule 2 – When we have to add two integers with different signs ( one is positive and other is negative), we find their difference, regardless of their signs, and give the sign of the integer with the greater value to such difference.

Example 5

Find the sum of 25 and 27?

Explanation

While adding two integers with the same sign, we add their values regardless of their signs, and give the sum, their common sign.
In present case,
First, we add the values of the two integers, regardless of the negative sign:
25 + 27 = 52
Now we would assign the common sign to the answer,
In present case the common sign is ( + )
So, the sum of 25 and 27 is +52 or 52

Example 6

Find the sum of (-47) and (-52)?

Explanation

While adding two integers with the same sign, we add their values regardless of their signs, and give the sum, their common sign.
In present case,
First, we add the values of the two integers, regardless of the negative sign:
47 + 52 = 99
Now we would assign the common sign to the answer,
In present case the common sign is ( – )
So, the sum of (-47) and (-52) is -99

Example 7

Find the sum of 68 and -32?

Explanation

When we have to add two integers with different signs ( one is positive and other is negative), we find their difference, regardless of their signs, and give the sign of the integer with the greater value to such difference.
In present case,
First we find the difference to the given integers i.e, 68 – 32 = 36
Now, we would assign the sign of the greater integer to the result.
In this case, 68 > 32
and the sign of 68 is ( + )
Hence, the sum of 68 and -32 is +36 or, 36

Example 8

Find the sum of -17 and 25?

Explanation

When we have to add two integers with different signs ( one is positive and other is negative), we find their difference, regardless of their signs, and give the sign of the integer with the greater value to such difference.
In present case,
First, we find the difference to the given integers i.e, 25 – 17 = 8
Now, we would assign the sign of the greater integer to the result.
In this case, 25 > 17
and the sign of 25 is ( + )
Hence, the sum of -17 and 25 is +8 or, 8

Integers Questions For Class 6 – Subtracting Integers

Example 9

Subtract:
64 – 50

Explanation

In order to subtract a smaller integer from a larger integer, where both the integers are positive, we subtract the smaller integer from the higher integer, and give the positive sign to the difference.
So, first we subtract the smaller integer from the higher integer.
64 – 50 = 14
Now, we assign positive sign to the result i.e, +14 or 14
Hence, 64 – 50 = 14

Example 10

Subtract:
53 – 79

Explanation

In order to subtract a larger integer from a smaller integer, where both the integers are positive, we subtract the smaller integer from the higher integer, and give the negative sign to the difference.
So, first we subtract the smaller integer from the higher integer.
79 – 53 = 26
Now, we assign negative sign to the result i.e, -26
Hence, 53 – 79 = -26

Example 11

Subtract:
( -31 ) – ( -15 )

Explanation 

In order to subtract a smaller integer from a larger integer, where both the integers are negative, we subtract the smaller integer from the higher integer, and give the negative sign to the difference.
In the present case, both – 31 and – 15 are negative.
Difference of the two integers, ignoring their signs :
= 31 – 15
= 16
Now, we assign negative sign to the result i.e, (-16)
Hence, ( -31 ) – ( -15 ) = (-16)

Example 12

Subtract:
( -19 ) – ( -34 )

Explanation

In order to subtract a larger integer from a smaller integer, where both the integers are negative, we subtract the smaller integer from the higher integer, and give the positive sign to the difference.
In the present case, both – 19 and – 34 are negative.
Difference of the two integers, ignoring their signs :
= 34 – 19
= 15
Now, we assign positive sign to the result i.e, (+15)
Hence, ( -19 ) – ( -34 ) = (+15) or 15

Example 13

Subtract:
( 7 ) – ( -13 )

Explanation

When we subtract a negative integer from a positive integer then, we add the two numbers.
Since, 7 is positive and 13 is negative
We simply Add the two integers, ignoring their signs:
= 13 + 7
= 20 or +20
Hence, ( 7 ) – ( -13 ) = +20 or 20

Example 14

Subtract:
( – 59 ) – ( 81 )

When we subtract a positive integer from a negative integer, we add the two integers and and give the negative sign to it.
Since, – 59 is negative and 81 is positive
We simply Add the two integers, ignoring their signs:
= 81 + 59
= 140
and assign negative sign to the result i.e, -140
Hence, ( -81 ) – ( 59 ) = -140

Integers Questions For Class 6 – Multiplication of Integers

Rule 1 – In order to find the product of two integers with same signs, we simply multiply the integers regardless of their signs and give a ( + ) positive sign to the product.

Rule 2 – In order to find the product of two integers with different signs, we simply multiply the integers regardless of their signs and give a ( – ) negative sign to the product.

Example 15

Multiply ( 10 ) by ( 7 ).

Explanation

In order to multiply two positive integers, we simply multiply the two integers, and add a positive sign to it.
Since, both 10 and 7 are positive
We simply multiply the integers:
10 x 7 = 70
and add the positive sign to the product + 70
Hence, 10 x 7 = +70 or 70

Example 16

Multiply ( -5 ) by ( -9 ).

Explanation

Multiplication of two negative integers is always a positive integer. In order to multiply two negative integers we simply multiply two numbers, and add a positive sign to it.
Since, both -5 and -9 are negative.
We simply multiply the two integers, ignoring their signs:
5 x 9 = 45
and add the positive sign to the product + 45
Hence, -5 x -9 = +45 or 45

Example 17

Multiply ( 4 ) by ( -7 ).

Explanation

Multiplication of one positive and one negative integer will always results in negative integer. In order to multiply a positive integer and a negative integer, we simply multiply the two numbers, and add a negative sign to it.
Since, 4 is positive and -7 is negative.
We simply multiply the two integers, ignoring their signs:
4 x 7 = 28
and add a negative sign to the result – 28
Hence, 4 x -7 = -28

Example 18

Multiply ( -7 ) by ( 8 ).

Explanation

Multiplication of one positive and one negative integer will always results in negative integer. In order to multiply a positive integer and a negative integer, we simply multiply the two numbers, and add a negative sign to it.
Since, -7 is negative and 8 is positive.
We simply multiply the two integers, ignoring their signs:
7 x 8 = 56
and add a negative sign to the result – 56
Hence, -7 x 8 = -56

Integers Questions For Class 6 – Dividing Integers

Rule 1 – Division of one positive integer by another positive integer, is always a positive integer. In order to divide two positive integers we simply divide the two numbers, and add a positive sign to it.

Rule 2 – Division of two negative integers is always a positive integer. In order to divide two negative integers we simply divide the two numbers, and add a positive sign to it.

Rule 3 – In order to divide a positive integer by a negative integer, we simply divide a positive integer by a negative integer and assign a negative sign to the result.

Rule 4 – In order to divide a negative integer by a positive integer, we simply divide a negative integer by a positive integer and assign a negative sign to the result.

Example 19

Divide 84 by 12

Explanation

Division of one positive integer by another positive integer, is always a positive integer. In order to divide two positive integers, we simply divide the two numbers and add a positive sign to it.
Since, both 84 and 12 are positive.
We simply divide one positive integer by another positive integer i.e,
84 ÷ 12 = 7
and add the positive sign to result i.e, + 7
Hence, 84 ÷ 12 = ( +7 ) or 7

Example 20

Divide ( -56 ) by ( -8 )

Explanation

Division of two negative integers is always a positive integer. In order to divide two negative integers, we simply divide the two numbers and add a positive sign to it.
Since, both -56 and -8 are negative.
We simply divide the two integers, ignoring their signs:
56 ÷ 8 = 7
Add the positive sign to result i.e, + 7
Hence, ( -56 ) ÷ ( -8 ) = ( +7 ) or 7

Example 21

Divide ( 48 ) by ( -6 )

Explanation

In order to divide a positive integer by a negative integer, we simply divide a positive integer by a negative integer and assign a negative sign to the result.
Since, ( 48 ) is positive and -6 is negative.
We simply divide the two integers, ignoring their signs:
( 48 ) ÷ 6 = 8
and assign the negative sign to result i.e, – 8
Hence, ( 48 ) ÷ ( -6 ) = ( -8 )

Example 22

Divide ( -56 ) by ( 8 )

Explanation

In order to divide a negative integer by a positive integer, we simply divide a negative integer by a positive integer and assign a negative sign to the result.
Since, ( -56 ) is negative and 8 is positive.
We simply divide the two integers, ignoring their signs:
( 56 ) ÷ 8 = 7
and assign the negative sign to result i.e, – 7
Hence, ( -56 ) ÷ ( 8 ) = ( -7 )

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