Express each number as a product of its prime factors (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

Question Express each number as a product of its prime factors (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429
Board CBSE
Textbook NCERT
Class  Class 10
Subject Maths
Chapter  Chapter 1 Real Numbers

Question – Express each number as a product of its prime factors (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

Solution:

(i) 140

For prime factors we take LCM of 140

140 = 2 × 2 × 5 × 7

= 22 × 5 × 7

Prime factors of 140 are 2, 5, 7

(ii) 156

For prime factors we take LCM of156

156 = 2 × 2 × 3 × 13

= 22 × 3 × 13

Prime factors of 156 are 2, 3, 13.

(iii) 3825

For prime factors we take LCM of 3825

3825 = 5 × 5 × 3 × 3 ×17

= 52 × 32 ×17

Prime factors of 3825 are 5, 3, 17.

(iv) 5005

For prime factors we take LCM of 5005

5005 = 5 × 7 × 11 × 13

Prime factors of 5005 are 5, 7, 11, 13.

(v) 7429

For prime factors we take LCM of 7429

7429 = 17 × 19 × 23

Prime factors of 7429 are 17, 19, 23.

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