Question | Express each number as a product of its prime factors (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429 |
Board | CBSE |
Textbook | NCERT |
Class | Class 10 |
Subject | Maths |
Chapter | Chapter 1 Real Numbers |
Question – Express each number as a product of its prime factors (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429
Solution:
(i) 140
For prime factors we take LCM of 140
140 = 2 × 2 × 5 × 7
= 22 × 5 × 7
Prime factors of 140 are 2, 5, 7
(ii) 156
For prime factors we take LCM of156
156 = 2 × 2 × 3 × 13
= 22 × 3 × 13
Prime factors of 156 are 2, 3, 13.
(iii) 3825
For prime factors we take LCM of 3825
3825 = 5 × 5 × 3 × 3 ×17
= 52 × 32 ×17
Prime factors of 3825 are 5, 3, 17.
(iv) 5005
For prime factors we take LCM of 5005
5005 = 5 × 7 × 11 × 13
Prime factors of 5005 are 5, 7, 11, 13.
(v) 7429
For prime factors we take LCM of 7429
7429 = 17 × 19 × 23
Prime factors of 7429 are 17, 19, 23.
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