Concept of Perimeter and Area Class 6 MCQ

Answer: (a) 60 cm²

Explanation: Given,
length = 6 cm

breadth = 10 cm

Area of rectangle = ( length x breadth ) cm²

= ( 6 x 10 ) cm²

= 60 cm²

Hence, the area of rectangle is 60 cm²

Answer: (b) 34 cm

Explanation: Rectangle is a four sided polygon having equal opposite sides

Given:

Length = 5 cm

Breadth = 12 cm

Perimeter of rectangle = 2 ( l + b ) units

= 2 ( 5 + 12 ) cm (Here, Length = 5 cm , Breadth = 12 cm )

= ( 2 x 17 ) cm

= 34 cm

Hence, Perimeter of rectangle is 34 cm.

Answer: (d) 56 cm

Explanation: Square is a four sided polygon having all four sides equal in length.
Given:

Side = 14 cm

Perimeter of square = ( 4 x Length of each side ) units

= ( 4 x 14 ) cm

= 56 cm

Hence, Perimeter of square is 56 cm

Answer: (d) 10 cm

Explanation: Triangle is a three sided polygon.
Given:
Ist side = 3.2 cm

IInd side = 4.3 cm

IIIrd side = 2.5 cm

Perimeter of triangle = Sum of its sides

= ( Ist side + IInd side + IIIrd side ) cm

= ( 3.2 + 4.3 + 2.5 ) cm

= 10 cm

Hence, Perimeter of triangle is 10 cm

Answer: (b) 15 cm

Explanation: An equilateral triangle is a triangle having all three sides equal in length.

Length of each side of an equilateral triangle = 5 cm

Perimeter of an equilateral triangle = ( 3 x Length of each side ) units

= ( 3 x 5 ) cm

= 15 cm

Hence, Perimeter of an equilateral triangle is 15 cm

Answer: (d) 35 cm

Explanation: A regular pentagon is a five sided polygon.

All the five sides of regular pentagon are equal.

So, Length of each side of regular pentagon = 7cm

Perimeter of a regular pentagon = ( 5 x Length of each side ) units

= ( 5 x 7 ) cm

= 35 cm

Hence, Perimeter of a regular pentagon is 35 cm

Answer: (b) 36.8 cm

Explanation: A regular octagon is an eight sided polygon.

All eight sides of regular octagon are equal.

So, Length of each side of regular octagon =4.6cm

Perimeter of a regular octagon = ( 8 x Length of each side ) units

= ( 8 x 4.6 ) cm

= 36.8 cm

Hence, Perimeter of a regular octagon is 36.8 cm

Answer: (b) 43 cm

Explanation: A regular decagon is a ten sided polygon that has all ten sides equal in length

Length of a regular decagon =4.3

Perimeter of a regular decagon =(10xLength of each side)units

=(10×4.3)cm

=43cm

Hence, Perimeter of a regular decagon is 43cm

Answer: (c) 28cm²

Explanation: Given,

length = 7 cm

breadth = 4 cm

Area of rectangle = ( length x breadth ) cm²

= ( 7 x 4 ) cm²

= 28 cm²

Hence, the area of rectangle is 28 cm²

Answer: (d) ₹ 6500

Explanation: Length of the field = 50 m

Breadth of the field = 80 m

Perimeter of the field = 2 ( l + b ) units

= 2 ( 50 + 80 ) m

= ( 2 x 130 ) m

= 260 m

Cost of fencing per metre = ₹ 25

Total cost of fencing = ₹ ( 260 x 25 )

= ₹ 6500

Answer: (d) 1200 m

Explanation: Length of the field = 40 m

Breadth of the field = 80 m

Perimeter of the field = 2 (l + b) units

= 2 ( 40 + 80 ) m

= ( 2 x 120 ) m

= 240 m

Total length of rope = 5 x Perimeter of the field

= ( 5 x 240 ) m

= 1200 m

Answer: (c) 702.25cm²

Explanation: Sides of square = 26.5cm

Area of square = ( side x side ) cm²

= ( 26.5 x 26.5 ) cm²

= 702.25 cm²

Hence, the area of square plot is 702.25 cm²

Answer: (d) 8.8. cm

Explanation: The radius of given circle is r = 1.4 cm

Circumference of the circle = 2πr

= ( 2 x (22/7)x 1.4 ) cm

= 8.8 cm

Hence, the circumference of the given circle is 8.8 cm

Answer: (b) 4.4 cm

Explanation: The diameter of given circle = 1.4 cm

Then, radius = Diameter/2 = 1.4/2cm = 0.7 cm

Circumference of circle = 2πr

= ( 2 x (22/7)x 0.7 ) cm

= 4.4 cm

Hence, the circumference of the given circle is 4.4 cm

Answer: (d) 14 cm

Explanation: Let, the radius of the given circle be r cm

As we know that,

Circumference of the circle = 2πr cm

Given,

Circumference of a circle = 88cm

2πr = 88 (from above)

r = 88/2π

= (88×7)/(2×22)

= 14cm

Hence, the radius of the circle = 14cm

Answer: (c) 12.6 cm

Explanation: Let, the radius of the given circle be r cm

As we know that,

Circumference of the circle = 2πr cm

Given,

Circumference of a circle = 39.6cm

Therefore,

2πr = 39.6 (from above)

r = 39.6/2π

= (39.6×7)/(2×22)

= 6.3cm

Diameter of the circle = 2r

= (2 x 6.3)cm

= 12.6 cm

Answer: (b) 0.132 km

Explanation: Radius of the wheel = 42/2 cm = 21 cm

Circumference of the wheel = 2πr

= ( 2 x (22/7)x 21 ) cm

= 132 cm

= 1.32 m ( As we know that, 1 m = 100 cm )

Distance covered by wheel in 1 revolution = Circumference of the wheel

Distance covered by wheel in 1 revolution = 1.32 m

Distance covered by wheel in 100 revolutions = ( 1.32 x 100 ) m

= 132 m

= 0.132 km ( As we know that, 1 m = 1000 km )

Hence, Distance covered by wheel in 100 revolutions is 0.132 km

Answer: (c) 40 cm

Explanation: Given

Area = 84 cm²

breadth = 14 cm

Length of the rectangle = (area in cm²)/(Breadth in cm) = 84cm²/14cm = 84cm/ 14 = 6 cm

Perimeter of the rectangle = 2 x ( l + b ) cm

= 2 x ( 14 + 6 ) cm

= ( 2 x 20 ) cm

= 40 cm

Hence, the perimeter of the rectangle is 40 cm

Answer: (c) 134 cm

Explanation: Given

Area = 660 cm²

length = 12 cm

Breadth of the rectangle = (area in cm²)/(Length in cm) = 660cm²/12cm = 660cm/12 = 55 cm

Perimeter of the rectangle = 2 x ( l + b ) cm

= 2 x ( 12 + 55 ) cm

= ( 2 x 67 ) cm

= 134 cm

Answer: (b) Length = 30 m , breadth = 6 m

Explanation: Let, length and breadth be 5y m and 1y m

Since, perimeter of rectangle = 2 (l+ b) units

= 2 ( 5 y + 1 y ) m

= ( 2 x 6 y ) m

= 12y m

But, perimeter of rectangle = 72 m

Since, 12 y = 72

y = 72/12

y = 6

So, length = ( 5 x 6 ) m = 30 m

breadth = ( 1 x 6 ) m = 6 m

Answer: (a) ₹ 1290

Explanation: Length of the room = 86 m

Breadth of the room = 15 m

Area of the floor of the room = ( 86 x 15 ) m²

= 1290 m²

Area of carpet required = 1290 m²

Length of the carpet = (area of carpet )/(Width of carpet) = 1290m²/20m = 1290m/20 = 64.5 m

Rate of carpeting = 20 per metre.

Cost of carpeting = ₹ ( 64.5 x 20 ) = ₹ 1290