Algebra Class 6 MCQ Questions

Answer: (a) 33

Explanation: Let the required number be x

If the Number is double itself, we get 2x

We know that,

2x + 12 = 78

Transposing + 12 to -12 (Addition Changes to Subtraction)

2x = 78 – 12

2x = 66

x =66/2

x = 33

The required number is x = 33

Answer: (c) 5

Explanation: Given Equation:

4a + 9 = 39 – 2a

In the given expression, write variables on one side and Exponents on other side

Therefore,

4a + 9 = 39 – 2a

Transposing + 9 to -9

4a + 2a = 39 – 9

Take “a” as common and add the variables

( 4 + 2 )a = 30

6a = 30

a = 30/6

Divide Numerator and Denominator with their HCF i.e., 6

a = (30÷6)/(6÷6)

a = 5/1

a = 5

Hence, the value of “a” is 5

Answer: (b) 23a = 575

Explanation: Suppose, the required number is ‘ a ‘

So, 23 times the number will be 23a

Therefore, 23a = 575

Hence, the Required Equation is

23a = 575

Answer: (b) False

Explanation: Given Equation :

7a – 40 = 9

Now, replace the value of a = 3 in the given equation

On substitution, the given equation becomes 7 x 3 – 40 = 9

According to BODMAS Rule, we will do multiplication first, i.e., 7 x 3 = 21

Therefore, the equation would now be 21 – 40 = 9 or -19 = 9

Which is not true

Therefore, LHS ≠ RHS

Hence, 3 is not the root of 7a – 40 = 9

Answer: (c) 2

Explanation: (8a+11)/9 = 3

On Cross Multiplying,

8a + 11 = 3 x 9

8a + 11 = 27

Transposing + 11 to -11 (Addition Changes to Subtraction)

8a = 27 – 11

8a = 16

On Cross Multiplying

a = 16/8

a = 16/8 = 2/1 = 2

Value of a = 2

Answer: (a) 2

Explanation: Given Equation is :

y + 24 = 26

Now, we will try several values of y, until we get LHS = RHS

Therefore, y = 2

Answer: (a) 80, 400

Explanation: Let number of the 50 paisa coins be x

As 25 paisa coins are 5 times of 50 paisa coins

Therefore, the number of 25 paisa coins will be ( 5x )

Now, we are given that

50x + 25( 5 × x  ) = 14000

Both the expressions have same Variable so we can add them,

or 50 × x + 125 x x = 14000

Take x as common

( 50 + 125 )x = 14000

175x = 14000

x = 14000/175

x = 80

Therefore the number of 50 paisa coins is 80

Number of 25 paisa coins = 5 × x

Number of 25 paisa coins = 5 × 80

Number of 25 paisa coins = 400

Answer: (c) 18

Explanation: Given Equation:

4a/3 = 24

On Cross Multiplication,

4a = 24 x 3

4a = 72

Therefore,

a =72/4

Dividing both the Numerator and Denominator by their HCF i.e., 4

a = (72÷4)/(4÷4) = 18/1 = 18

So, the value of ‘a’ = 18

Answer: (c) 28 , 45

Explanation: Let the present age of Akash be 1a

Since Ankur is 17 years older than Akash

Present age of Ankur will be ( 1a + 17 ) years

Given,

Sum of their ages = 73

i.e.,

1a + ( 1a + 17 ) = 73

Take “a” as common

( 1 + 1 )a + 17 = 73

2a + 17 = 73

Transposing + 17 to -17 (Addition Changes to Subtraction)

2a = 73 – 17

2a = 56

or in other words

a =56/2

a = 28

Present age of Akash = 28 Years

Present age of Ankur = (1 x a + 17) years

= (1 x 28 + 17) years

= 45 years

Answer: (c) 36

Explanation: Step 1 : B – Remove Brackets

Step 2 : O – “O” stand for “OF” which means multiply

Step 3 : D – Division

Step 4 : M – Multiplication

Step 5 : A – Addition

Step 6 : S – Subtraction

Given expression:

8 + 7 x 4

Since there are no brackets, ‘of’ and Divide. So, Step I, Step 2 and Step 3 are not Applicable.

We perform Step 4: Multiplication

= 8 + 28

Then, we perform Step 5: Addition

= 36

Answer: (a) 12

Explanation: Step 1 : B – Remove Brackets

Step 2 : O – “O” stand for “OF” which means multiply

Step 3 : D – Division

Step 4 : M – Multiplication

Step 5 : A – Addition

Step 6 : S – Subtraction

Given expression:

42 – 5 x 6

Since there are no brackets, ‘of’ and Divide. So, Step I, Step 2 and Step 3 are not Applicable.

We perform Step 4: Multiplication

= 42 – 30

Since, there is no subtraction, Step 5 is not applicable

Then, we perform Step 6: Subtraction

= 12

Answer: (b) 9

Explanation: Step 1 : B – Remove Brackets

Step 2 : O – “O” stand for “OF” which means multiply

Step 3 : D – Division

Step 4 : M – Multiplication

Step 5 : A – Addition

Step 6 : S – Subtraction

Given expression:

6 + 18 ÷ 6

Since there are no brackets and ‘of’ . So, Step I and Step 2 are not Applicable.

We perform Step 3: Division

= 6 + 3

Since, there is no Multiplication, Step 4 is not applicable

Then, we perform Step 5: Addition

= 9

Answer: (c) 52

Explanation: Step 1 : B – Remove Brackets

Step 2 : O – “O” stand for “OF” which means multiply

Step 3 : D – Division

Step 4 : M – Multiplication

Step 5 : A – Addition

Step 6 : S – Subtraction

Given expression:

55 – 15 ÷ 5

Since there are no brackets and ‘of’ . So, Step I and Step 2 are not Applicable.

We perform Step 3: Division

= 55 – 3

Since, there are no multiplication and addition, Step 4 and Step 5 are not applicable

Then, we perform Step 6: Subtraction

= 52

Answer: (c) 28

Explanation: Step 1 : B – Remove Brackets

Step 2 : O – “O” stand for “OF” which means multiply

Step 3 : D – Division

Step 4 : M – Multiplication

Step 5 : A – Addition

Step 6 : S – Subtraction

Given expression:

13 + 25 ÷ 5 x 3

Since there are no brackets and ‘of’ . So, Step I and Step 2 are not Applicable.

We perform Step 3: Division

= 13 + 5 x 3

Then, we perform Step 4: Multiplication

= 13 + 15

Then, we perform Step 5: Addition

= 28

Answer: (b) 13

Explanation: Step 1 : B – Remove Brackets

Step 2 : O – “O” stand for “OF” which means multiply

Step 3 : D – Division

Step 4 : M – Multiplication

Step 5 : A – Addition

Step 6 : S – Subtraction

Given expression:

25 – 10 ÷ 5 x 6

Since there are no brackets and ‘of’ . So, Step I and Step 2 are not Applicable.

We perform Step 3: Division

= 25 – 2 x 6

Then, we perform Step 4: Multiplication

= 25 – 12

Since, there is no addition, Step 5 is not applicable

Then, we perform Step 6: Subtraction

= 13

Answer: (c) 29

Explanation: Step 1 : B – Remove Brackets

Step 2 : O – “O” stand for “OF” which means multiply

Step 3 : D – Division

Step 4 : M – Multiplication

Step 5 : A – Addition

Step 6 : S – Subtraction

Given expression:

5 + 4 x 12 ÷ 2

Since there are no brackets and ‘of’ . So, Step I and Step 2 are not Applicable.

We perform Step 3: Division

= 5 + 4 x 6

Then, we perform Step 4: Multiplication

= 5 + 24

Then, we perform Step 5: Addition

= 29

Answer: (b) 57

Explanation: Step 1 : B – Remove Brackets

Step 2 : O – “O” stand for “OF” which means multiply

Step 3 : D – Division

Step 4 : M – Multiplication

Step 5 : A – Addition

Step 6 : S – Subtraction

Given expression:

73 – 4 x 24 ÷ 6

Since there are no brackets and ‘of’ . So, Step I and Step 2 are not Applicable.

We perform Step 3: Division

= 73 – 4 x 4

Then, we perform Step 4: Multiplication

= 73 – 16

Since, there is no addition, Step 5 is not applicable

Then, we perform Step 6: Subtraction

= 57

Answer: (b) 12

Explanation: Step 1 : B – Remove Brackets

Step 2 : O – “O” stand for “OF” which means multiply

Step 3 : D – Division

Step 4 : M – Multiplication

Step 5 : A – Addition

Step 6 : S – Subtraction

Given expression:

15 + 25 ÷ 5 – 2 x 4

Since there are no brackets and ‘of’ . So, Step I and Step 2 are not Applicable.

We perform Step 3: Division

= 15 + 5 – 2 x 4

Then, we perform Step 4: Multiplication

= 15 + 5 – 8

Then, we perform Step 5: Addition

= 20 – 8

At last we perform Step 6: Subtraction

= 12

Answer: (b) 81

Explanation: Step 1 : B – Remove Brackets

Step 2 : O – “O” stand for “OF” which means multiply

Step 3 : D – Division

Step 4 : M – Multiplication

Step 5 : A – Addition

Step 6 : S – Subtraction

Given expression:

40 – 35 ÷ 5 + 6 x 8

Since there are no brackets and ‘of’ . So, Step I and Step 2 are not Applicable.

We perform Step 3: Division

= 40 – 7 + 6 x 8

Then, we perform Step 4: Multiplication

= 40 – 7 + 48

Then, we perform Step 5: Addition

= 88 – 7

At last we perform Step 6: Subtraction

= 81

Answer: (b) 5, 9, 3

Explanation: 5xy + 9x + 3y

In the given expression, various terms are as under: –

5xy – Numerical Coefficient of 5xy is 5.

9x – Numerical Coefficient of 9x is 9.

3y – Numerical Coefficient of 3y is 3.

Answer: (b) Unlike terms

Explanation: When two terms have same variables and same power of each variable then those terms are called like terms otherwise unlike terms. The constant can be different. All constants are like terms.

The given terms are Unlike Terms, since both the terms have different variables , i.e., the first term 13ab² has a variable ab² and the second term 18a²b has a variable a²b

Answer: (b) 9a¹b⁵

Explanation: ​9 x a x b x b x b x b x b

here, a is multiplied by itself 1 times. So we can write it as a¹

here, b is multiplied by itself 5 times. So we can write it as b⁵

or, we can also write it as,

9a¹b⁵

Answer: (a) 70

Explanation: Given:

a = 8

b = 5

Given expression

5 a +6 b

Now we will replace a = 8 and b = 5

= ( 5 x a ) + ( 6 x b )

= ( 5 x 8 ) + ( 6 x 5 )

According to BODMAS rule we will do multiplication first

= 40 + 30

then, Addition

= 70

Answer: (b) False

Explanation: LHS: 3a + 4b

Substitute the value, a = 5 and b = 3 in the given expression

We get,

( 3 x a ) + ( 4 x b )

= ( 3 x 5 ) + ( 4 x 3 )

According to BODMAS rule we will do multiplication first

= 15 + 12

then, Addition

= 27

On Solving RHS,

RHS = 4c

Substituting the value , c = 4

RHS = 4 x 4

RHS = 16

Hence, LHS ≠ RHS

So, the above expression is FALSE.

Answer: (c) 10a

Explanation: Given Expression :

25a and 15a

Both the expression have same Variable so we can substract them,

Here,

Constants = 25 and 15

Variable = a

Therefore,

25a – 15a

Taking ” a ” as common we get

= ( 25 – 15 )a

= 10a

Answer: (c) 9a

Explanation: Given Expression :

26a and 17a

Both the expression have same Variable so we can substract them,

Here,

Constants = 26 and 17

Variable = a

Therefore,

26a – 17a

Taking ” a ” as common we get

= ( 26 – 17 )a

= 9a

Answer: (a) 35a

Explanation: Since both the expression have same Variable, we can add them

Given expression are 47a and -12a

Here 47 and -12 are constants

and ” a ” is variable

47 x a + ( -12 ) x a

Taking “a” as common

= [47 + ( -12 ) ]a

= [47 – 12 ]a

= 35a