Find the product using suitable properties. (a) 738 × 103 (b) 854 × 102 (c) 258 × 1008 (d) 1005 × 168

Board CBSE
Textbook NCERT
Class  Class 6
Subject Maths
Chapter  Chapter 2 Whole Numbers

Question – Find the product using suitable properties
(a) 738 × 103
(b) 854 × 102
(c) 258 × 1008
(d) 1005 × 168

Solution

(a) 738 × 103

On rearranging, we get

= 738 × (100 + 3)

[By distributive property i.e., (a+ b)× c = a× c + c× b]

= (738 × 100) + (738 × 3)

Multiplying the numbers in the parentheses, we get

= 73,800 + 2,214

= 76,014

(b) 854 × 102

On rearranging, we get

= 854 × (100 + 2)

[By distributive property i.e., (a+ b)× c = a× c + c× b]

= (854 × 100) + (854 × 2)

Multiplying the numbers in the parentheses, we get

= 85,400 + 1708

= 87,108

(c) 258 × 1008

On rearranging, we get

= 258 × (1000 + 8)

[By distributive property i.e., (a+ b)× c = a× c + c× b]

= (258 × 1000) + (258 × 8)

Multiplying the numbers in the parentheses, we get

= 258000 + 2064

= 2,60,064

(d) 1005 × 168

On rearranging, we get

= (1000 + 5) × 168

[By distributive property i.e., (a+ b)× c = a× c + c× b]

= (1000 × 168) + (5 × 168)

Multiplying the numbers in the parentheses, we get

= 168000 + 840

= 1,68,840

Hence,
(a) 738 × 103 = 76,014
(b) 854 × 102 = 87,108
(c) 258 × 1008 = 2,60,064
(d) 1005 × 168= 1,68,840

 

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