Constructions Class 9 MCQ

Constructions Class 9 MCQ – Maths Class 9 MCQ Online Test are covered in this Article. Constructions Class 9 MCQ Test contains 25 questions. Answers to MCQ on Constructions Class 9 are available after clicking on the answer. MCQ Questions for Class 9 with Answers have been made for Class 9 students to help check the concept you have learnt from detailed classroom sessions and application of your knowledge.

Board CBSE
Textbook Maths (NCERT)
Class Class 9
Chapter Chapter 11 Constructions
Category MCQ Questions for Class 9 Maths with Answers

Constructions Class 9 MCQ

1. An end- to- end testing framework for angular applications is

(a) Angle

(b) Compass

(c) Protractor

(d) Scale

Answer

Answer: (c) Protractor


 

2. In a given figure, name the angle bisected

(a) ∠AOB

(b) ∠AOC

(c) ∠COB

(d) OB

Answer

Answer: (b) ∠AOC

Explanation: Here, OB bisects ∠AOC.


 

3. Measured constructions required following instruments

(a) Scale

(b) Compass

(c) Protractor

(d) All of the above

Answer

Answer: (d) All of the above


 

4. In a triangle PQR, PQ= PR= 4cm, ∠Q = 60˚, find ∠P

(a) 80˚

(b) 60˚

(c) 40˚

(d) 50˚

Answer

Answer: (b) 60˚

Explanation:

Here, PQ= PR= 4cm

Therefore, ∠Q = ∠R = 60˚ (Angles opposite to equal sides are equal)

In ∆PQR, ∠P + ∠Q + ∠R = 180˚ (angle sum property)

∠P + 60˚ + 60˚ = 180˚

∠P = 180˚ – 120˚ = 60˚





5. Angles can be constructed using only protractor are

(a) 60˚

(b) 45˚

(c) 15˚

(d) All of the above

Answer

Answer: (d) All of the above


 

6. Write the measure of given angle A.

(a) 180˚

(b) 90˚

(c) 100˚

(d) 360˚

Answer

Answer: (a) 180˚

Explanation: The given figure is straight line. So, ∠A = 180˚


 

7. If p, q, r are the sides of a triangle ABC, then

(a) p + q = r

(b) p + r = q

(c) p + q > r

(d) p + q < r

Answer

Answer: (c) p + q > r

Explanation: The sum of two sides of a triangle is always greater than the third side.


 

Constructions Class 9 MCQ

8. The construction of ∆PQR is not possible if

(i) PQ + PR = QR

(ii) PQ + PR > QR

(iii) PQ + PR < QR

(a) Satisfying i, ii, iii

(b) Satisfying i and ii

(c) Satisfying i and iii

(d) Satisfying ii and iii

Answer

Answer: (c) Satisfying i and iii

Explanation: The construction of any triangle is not possible if the sum of two sides is lesser or equal to its third side.


 

9. Name the instruments used to draw the perpendicular bisector of a given line segment.

(a) Ruler and compass

(b) Ruler and protractor

(c) Protractor and compass

(d) Compass

Answer

Answer: (a) Ruler and compass

Explanation:


 

10. To construct an angle bisector, we need to use

(a) Ruler, compass and protractor

(b) Ruler and compass

(c) Compass and protractor

(d) Ruler and protractor

Answer

Answer: (b) Ruler and compass

Explanation: Ruler and compass are needed to construct an angle bisector


 

 

11. The perimeter of an isosceles triangle ABC is 36cm. Construct a triangle with AB= 8cm, ∠C = 80˚ and AC=?

(a) AC = BC = 14cm

(b) AC = BC = 10cm

(c) AC = BC = 9cm

(d) AC = BC = 8cm

Answer

Answer: (a) AC = BC = 14cm

Explanation:

Two sides of an isosceles triangles are equal.

In ∆ABC, AC = BC, AB = 8cm

Perimeter = AB +AC + BC

36= 8 + AC +AC

AC = 14cm

AC = BC =14cm


 

12. 22(1/2)˚ is a bisector of

(a) 60˚

(b) 30˚

(c) 45˚

(d) 50˚

Answer

Answer: (c) 45˚

Explanation: Bisector of 45˚ = 45˚/2 = 22(1/2)˚


 

13. What could be the length of QR to construct a ∆PQR when PQ = 3.5cm and PR = 4.5cm.

(a) 8cm

(b) 5cm

(c) 10cm

(d) 5cm

Answer

Answer: (d) 5cm

Explanation:

The construction of any triangle is possible if the sum of two sides of a triangle is always greater than the third side.

PQ + PR > QR

3.5 + 4.5 > QR

8 > QR

(The only option satisfying this condition is D)





14. Which is the correct statement if the length of sides of a triangle are m, n, o.

(a) m + n <o

(b) m – n < o

(c) m + n = o

(d) m – n > o

Answer

Answer: (b) m – n < o


 

 15. ….………is a line that divides the line segment into two parts of equal measurements.

(a) Bisector

(b) Perpendicular bisector

(c) Midline

(d) Altitude

Answer

Answer: (b) Perpendicular bisector


 

 16. The bisector of ∠A & ∠B of triangle are

(a) Equal

(b) Parallel

(c) Congruent

(d) concurrent

Answer

Answer: (d) concurrent

Explanation: The bisector of angles of triangle are concurrent.


 

Constructions Class 9 MCQ

17. The right bisector of a line segment is passes through its

(a) Midpoint

(b) endpoint

(c) Any point

(d) None of the above

Answer

Answer: (a) Midpoint


 

18. The right bisectors of the sides of an ……… triangle intersects each other inside the triangle

(a) Right

(b) Obtuse

(c) Acute

(d) Equiangular

Answer

Answer: (c) Acute


 

19. Find the set of length of sides of a triangle is correct

(a) 2cm, 3cm, 5.5cm

(b) 9cm, 1.6cm, 2.5cm

(c) 5cm, 5cm, 8.5cm

(d) 2cm, 2.2cm, 4.5cm

Answer

Answer: (d) 2cm, 2.2cm, 4.5cm

Explanation: Only option D satisfy, the sum of two sides of a triangle is always greater than the third side.


 

20. Which angle can be constructed with the help of ruler and compass?

(a) 50˚

(b) 100˚

(c) 40˚

(d) None of the above

Answer

Answer: (d) None of the above


 

21. The right bisectors of the sides of an ……… triangle intersects each other outside the triangle

(a) Right

(b) Obtuse

(c) Acute

(d) Equiangular

Answer

Answer: (b) Obtuse





22. Right angle is the bisector of a

(a) Acute angle

(b) Obtuse angle

(c) Straight line

(d) Complete angle

Answer

Answer: (c) Straight line

Explanation:

Straight line has 180˚

Bisector of it = 180˚ /2 = 90˚ (right angle)


 

23. ….………. forms a circle around a point.

(a) Acute angle

(b) Obtuse angle

(c) Straight line

(d) Complete angle

Answer

Answer: (d) Complete angle


 

24. The bisectors of base angles of a triangle cannot enclose a right angle in any case.

(a) True

(b) False

Answer

Answer: (a) True

Explanation:

In ∆BDC,

∠D + ∠DBC + ∠ DCB = 180˚

∠D + ∠B/2 + ∠C /2 =180˚

∠D = 180˚ – (∠B/2 + ∠C /2) ……. (i)

In ∆ABC,

∠A + ∠B + ∠C = 180˚

∠B + ∠C = 180˚ – ∠A

∠B/2 + ∠C /2 = 90˚ – ∠A / 2…………. (ii)

From i & ii,

∠D = 180˚ – (90˚ – ∠A / 2)

∠D = 90˚ + ∠A / 2

So, ∠D can never be less than or equal to 90˚.


 

25. The point of concurrency of angle bisectors of a triangle is

(a) Orthocenter

(b) Incenter

(c) Centroid

(d) circumcenter

Answer

Answer: (b) Incenter


 

MCQ Questions for Class 9 Maths

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